Previous year questions give guidance to us and provide a base for the preparation of any competitive exam. It is always good to have an experience of how the level of exam varies from year to year. For every subject like in Quantitative Aptitude, we come to know the pattern of questions must be followed to prepare the examination.
(1-5) In
each of the following questions, two equations are given. You have to solve
them and answer the question.
If x>y
If x>y
If x
If x<y
If x=y or relationship cannot be established
If x>y
If x>y
If x
If x=y or relationship cannot be established
निम्नलिखित प्रश्नों में दो समीकरण (I) और (II) दिये गये है दोनों समीकरण हल कीजिए और प्रश्नों के उत्तर दीजिए-
यदि x>y
यदि x>y
यदि x
यदि x<y
यदि x=y या सम्बन्ध स्थापित नहीं किया जा सकता है।
यदि x>y
यदि x
यदि x=y या सम्बन्ध स्थापित नहीं किया जा सकता है।
If x > y/यदि x >
y
If x = y or Relationship cannot be established /यदि x = y
सम्बन्ध स्थापित नहीं किया जा सकता है।
1.) (I) 6x2-11x+4=0 (II) 30 y2 -23y+3=0
Sol
x = 1.33 , 0.5
y = 0.166, 0.6
Relationship cannot be established / सम्बन्ध स्थापित नहीं किया जा सकता है।
2.) (I) 7x2+10x+3=0 (II) 2y2+11y+14=0
Sol
x = –1, –0.429
y = –3.5, –2
x > y
3.) (I) 2x2 – 15 = 7x (II) 17y = – 7 – 6y2
Sol
x = +5, – 1.5
y = –2.33, – 0.5
Relationship cannot be established / सम्बन्ध स्थापित नहीं किया जा सकता है।
4) (I) 6x2 + 31x + 35 =
0 (II) 2y2 +
3y +1 = 0
Sol
x = –3.5, –1.66
y = – 1, – 0.5
x < y
Sol
x = 1.802, 2
y = 1.802, 1.8
x > y
