Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concept of all the topic so you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern. So that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.
Mahendra Guru provides you a Bank Quiz of Quantitative Aptitude on daily basis to help you in your preparation for Govt job. You can clear your doubts before an exam. Mahendra Guru also provides you an important note and study material for all subject and test through its website, Mahendra Guru App and YouTube channel apart from it Speed Test Portal. Most of these preparation products are also available for purchase on my shop. You can also visit Mahendras.org to get more information about our endeavour for your success. You can also study in details through our E-Mahendras Facebook and Mahendra Guru YouTube channel of Quantitative Aptitude.Q. 1 - P and Q can do a piece of work in 24 and 30 days respectively. Both started the work and worked for 6 days. Then Q leaves the work and R joins and the remaining work is completed by P and R together in 11 days. Find the days in which R alone can do the work.
(1) 80 days/दिन
(2) 100 days/दिन
(3) 120 days/दिन
(4) 130 days/दिन
(5) None of these/इनमें से कोई नहीं
Sol. (3) -
Q. 2 – Sakshi borrows Rs.7000 at simple Interest from Tanshika. At the end of 3 years, she again borrows Rs.3000 and settled that amount after paying Rs.4615 as interest after 8 years from the time she made the first borrowing. What is the rate of interest?
साक्षी 7000 रु. तनिष्का से उधार लेती है | 3 वर्ष के अंत में, वह 3000 रु. दोबारा उधार लेती है और उस राशि को पहली बार से उधार लेने के बाद के समय से 8 वर्ष बाद रु.4615 ब्याज के रूप में चुका कर अदा करती है | ब्याज की दर है ?
(1) 5.5%
(2) 6.5%
(3) 7.5%
(4) 9.5%
(5) None of these/इनमें से कोई नहीं
Sol. (2) – SI for Rs.7000 for 8 years/ 8 वर्ष में 7000 रु. पर साधारण ब्याज =
Again borrowed/ दोबारा उधार ली गयी राशि =3000
SI/ साधारण ब्याज =
Total interest/ कुल ब्याज =
560R + 150R = 4615
710R = 4615
R = 6.5%
Q. 3 – Dipika found that she had made a loss of 10% while selling his smartphone. She also found that if she sold it for Rs.50 more, she would have made a profit of 5%. The initial loss was what percentage of the profit earned, had she sold the smartphone for a 5% profit?
दीपिका ज्ञात करती है कि उसे अपना स्मार्टफोन बेचते समय 10% की हानि हुई | वह यह भी ज्ञात करती है कि यदि वह इसे 50 रु. अधिक में बेचती तो वह 5% का लाभ प्राप्त करती | प्रारम्भिक हानि प्राप्त लाभ का कितना प्रतिशत है, यदि वह स्मार्टफोन को 5% लाभ पर बेचती है ?
(1) 75%
(2) 85%
(3) 100%
(4) 200%
(5) None of these/इनमें से कोई नहीं
Sol. (4) –
Profit/लाभ = 5%
5% of CP/ क्रय मूल्य का 5% = Rs./रु.50
CP/क्रय मूल्य = Rs./रु.1000
Now/अब, Loss/हानि% = 10%
Loss/हानि = Rs.100
Required/अभीष्ट % =
Q. 4 – A slice from a circular pizza of diameter 14 inches is cut in such a way that each slice of pizza has a central angle of 45°. What is the area of each slice of Pizza (in square inches)?
एक वृत्ताकार पिज़्ज़ा में से एक टुकड़ा इस प्रकार काटा जाता है कि प्रत्येक टुकड़ा एक 45° का एक केंद्रीय कोण बनाता है | पिज़्ज़ा के टुकड़े का क्षेत्रफल (वर्ग इंच) में क्या है ?
(1) 16.25
(2) 19.25
(3) 18.25
(4) 17.25
(5) None of these/इनमें से कोई नहीं
Sol. (2) – Area of each pizza/प्रत्येक पिज़्ज़ा का क्षेत्रफल = πr2 ×
=
= 19.25
Q. 5 – Two persons Praveen and Suresh invested in a business with 115000 and 75000 rupees respectively. They agree that 40% of the profit should be divided equally among them and rest is divided between them according to their investment. If Praveen got 500 rupee more than Suresh, then the total profit is
.
दो व्यक्ति प्रवीण और सुरेश क्रमशः 115000 और 75000 रु. लगाकर एक व्यापार शुरू करते हैं | वे इस बात पर स्वीकार्यता करते हैं कि लाभ का 40% हिस्सा उनमें बराबर बराबर बाँट दिया जाएगा और शेष को उनके पूंजियों के अनुपात में बांटा जाएगा | यदि प्रवीण सुरेश से 500 रु. अधिक प्राप्त करता है, तो कुल लाभ है
(1) Rs./रु.3599.34
(2) Rs./रु.699.34
(3) Rs./रु.3958.34
(4) Rs./रु.999.34
(5) None of these/इनमें से कोई नहीं
Sol. (3) –
Let total profit be Rs.x/माना कुल लाभ x रु. है |
According to the question/प्रश्नानुसार,
Q. 6 – In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
निम्नलिखित प्रश्नों में दो समीकरण I और II दी गयी हैं | आपको उन्हें हल करना है और उत्तर देना है |
I. 36p + 64 = 0
II. q + (4)2 = 0
(1) p > q
(2) p < q
(3) p > q
(4) p < q
(5) p = q or no relation between p and q can be established/p और q के मध्य कोई सम्बन्ध स्थापित नहीं किया जा सकता है |
Sol. (1) –
p = - 1.33
q = - 1.77
Hence/अतः, p > q
Q. 7 – In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
निम्नलिखित प्रश्नों में दो समीकरण I और II दी गयी हैं | आपको उन्हें हल करना है और उत्तर देना है |
I.
II. (q + 2)(27 - q) = 210
(1) p > q
(2) p < q
(3) p > q
(4) p < q
(5) p = q or no relation between p and q can be established/p और q के मध्य कोई सम्बन्ध स्थापित नहीं किया जा सकता है |
Sol. (2) –
p = 7, -3
q = 12, 13
Hence/अतः, p < q
Q. 8 – In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
निम्नलिखित प्रश्नों में दो समीकरण I और II दी गयी हैं | आपको उन्हें हल करना है और उत्तर देना है |
I. p(35 - p) = 124
II. q(2q + 3) = 90
(1) p > q
(2) p < q
(3) p > q
(4) p < q
(5) p = q or no relation between p and q can be established/p और q के मध्य कोई सम्बन्ध स्थापित नहीं किया जा सकता है |
Sol. (5) –
I. p(35 - p) = 124
p2 - 35p + 124 = 0
p2 - 31p - 4p + 124 = 0
p(p - 31) - 4(p - 31) = 0
p = 31, 4
II. q(2q + 3) = 90
2q2 + 3q - 90 = 0
2q2 + 15q - 12q - 90 = 0
2q(q + 7.5) - 12(q + 7.5) = 0
q = - 7.5, 6
Hence relationship cannot be established/अतः कोई सम्बन्ध स्थापित नहीं किया जा सकता है |
Q. 9 – In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
निम्नलिखित प्रश्नों में दो समीकरण I और II दी गयी हैं | आपको उन्हें हल करना है और उत्तर देना है |
I. 2p² - 9p + 10 = 0
II. q² - 18q + 72 = 0
(1) p > q
(2) p < q
(3) p > q
(4) p < q
(5) p = q or no relation between p and q can be established/p और q के मध्य कोई सम्बन्ध स्थापित नहीं किया जा सकता है |
Sol. (2) –
I. 2p2 - 9p + 10 = 0
2p2 - 5p - 4p + 10 = 0
2p (p - 2.5) - 4 (p - 2.5) = 0
p = 2.5, 2
II. q2 - 18p + 72 = 0
q2 - 12p - 6q + 72 = 0
q (q - 12) - 6 (q - 12) = 0
q = 12, 6
Hence/अतः, p < q
Q. 10 – In the following questions two equations numbered I and II are given. You have to solve both the equations and give answer
निम्नलिखित प्रश्नों में दो समीकरण I और II दी गयी हैं | आपको उन्हें हल करना है और उत्तर देना है |
I. p² + 30p + 221 = 0
II. q² - 53q + 196 = 0
(1) p > q
(2) p < q
(3) p > q
(4) p < q
(5) p = q or no relation between p and q can be established/p और q के मध्य कोई सम्बन्ध स्थापित नहीं किया जा सकता है |
Sol. (2) –
I. p2 + 30p + 221 = 0
(p + 13) (p + 17) = 0
p = - 13, - 17
II. q2 - 53q + 196 = 0
(q - 49) (q - 4) = 0
q = 49, 4
Hence/अतः, p < q
Answer Key:
1. (3)
2. (2)
3. (4)
4. (2)
5. (3)
6. (1)
7. (2)
8. (5)
9. (2)
10. (2)
0 comments:
Post a Comment
MAHENDRA GURU