Quantitative Aptitude Questions For IBPS Clerk Mains : 12 - 01 - 18

1. 

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Q.1 What value will come in place of question mark (?) in the number-series given below?

निम्नलिखित संख्या श्रृंखला में प्रश्नचिन्ह (?) के स्थान पर क्या मान आयेगा

8 12 23 53 138 ? 

1. 384 
2. 382 
3. 386 
4. 387 
5. None of these 

Solutions 3 

Q.2 What value will come in place of question mark (?) in the number-series given below?

निम्नलिखित संख्या श्रृंखला में प्रश्नचिन्ह (?) के स्थान पर क्या मान आयेगा 

13 61 ? 349 733 1501 

1. 157 
2. 152 
3. 153 
4. 155 
5. None of these 

Solutions 1 

× 2 + 35, × 2 + 35, × 2 + 35, × 2 + 35, × 2 + 35

Q.3 What value will come in place of question mark (?) in the number-series given below?

निम्नलिखित संख्या श्रृंखला में प्रश्नचिन्ह (?) के स्थान पर क्या मान आयेगा 

4 9 15 27.5 ? 150.5 

1. 56 
2. 59 
3. 60 
4. 63 
5. None of these 

Solutions 2 

× 0.5 + 7, × 1 + 6, × 1.5 + 5, × 2 + 4, × 2.5 + 3

Q.4 The length of a room floor exceeds its breadth by 25 m. The area of the floor remains unaltered when the length is decreased by 10 m but the breadth is increased by 8 m. The area of the floor is 

कमरे की फर्श की लम्बाई फर्श की चौड़ाई से 25 मी. अधिक है। यदि फर्श की लम्बाई 10 मी. कम कर दी जाये और चौड़ाई 8 मी. बढ़ा दी जाये, तो फर्श का क्षेत्रफल अपरिवर्तित रहता है, फर्श का क्षेत्रफल है- 

1. 5400 m.²
2. 5600 m.²
3. 4800 m.²
4. 5100 m.²
5. None of these

Solutions 4

Let the breadth of floor be b m.
Then, length of the floor be (b + 25)
Area = (b + 25) × b
According to the question,
(b + 15) (b + 8) = (b + 25) × b
b2 + 8b + 15b + 120 = b² + 25b
2b = 120
b = 60 m.
l = b + 25 = 60 + 25 = 85 m.
Area of the floor = 85 × 60 = 5100 m.²

माना फर्श की चौड़ाई b मी. है |
तो, फर्श की लम्बाई (b + 25) होगी |
क्षेत्रफल = (b + 25) × b
प्रश्नानुसार,
(b + 15) (b + 8) = (b + 25) × b
b2 + 8b + 15b + 120 = b² + 25b
2b = 120
b = 60 मी.
l = b + 25 = 60 + 25 = 85 मी.
फर्श का क्षेत्रफल = 85 × 60 = 5100 मी.²

Q.5 Two trains x and y starts from station A and B towards B and A respectively. After passing each other they take 4 hours 48 minutes and 3 hours 20 minutes to reach B and A respectively. If train x is moving at 60 km/hr. Then find the speed of train y? 

दो रेलगाड़ियों x तथा y दो स्टेशनों A और B से एक दूसरे की तरफ चली। एक दूसरे को पार करने के बाद उन्हें B और A तक पहुँचने में क्रमशः 4 घण्टे 48 मिनट तथा 3 घण्टे 20 मिनट लगे। यदि रेलगाड़ी की गति 60 किमी./घण्टे हो तो रेलगाड़ी y की गति ज्ञात कीजिए 

1. 64 kmph 
2. 48 kmph 
3. 72 kmph 
4. 68 kmph 
5. None of these 

Solutions 3

We know that,

s2 = 72 kmph

Q.6 A committee of 5 members is to be formed out of 4 Lawyers, 3 Engineers and 2 Doctors. In how many ways a committee of 2 Lawyers, 2 Engineers and 1 Doctor can be formed ?

4 वकील, 3 इंजीनियर और 2 डॉक्टर में से 5 सदस्यों की एक समिति बनानी है । 2 वकील, 2 इंजीनियर और 1 डॉक्टर की समिति कितने तरीकों से बनाई जा सकती है ? 

1. 25 
2. 64 
3. 9 
4. 36 
5. None of these 

Solutions 4

Required ways = 4C2× 3C2× 2C1 = 36

Q.7. The ratio of largest angle and second largest angle is 3 : 2.The smallest angle is 20% of the sum of largest angle and second largest angle. What is the difference between largest angle and second largest angle?

एक त्रिभुज के सबसे बड़े और दूसरे सबसे बड़े कोण का अनुपात क्रमशः 3 : 2 है। सबसे छोटा कोण, सबसे बड़े और दूसरे सबसे बड़े कोण के योग का 20% है। सबसे बड़े और दूसरे सबसे बड़े कोण के बीच अन्तर क्या है? 

1. 20^o
2. 10^o
3. 40^o
4. 50^o
5. None of these

Solutions 5

x + y + z = 180⁰    ------(I)
z = (x + y) × 20/100
x + y = 5z           ------(II)
Statement (I) and (II)
6z = 180⁰
z = 30⁰
x : y = 3 : 2
x + y = 150⁰
x = 90⁰
y = 60⁰
Difference = 90⁰ - 60⁰ = 30⁰

Q.8. What approximate value will come in place of question mark (?) in the following question? 

निम्नलिखित प्रश्न में प्रश्नचिह्न (?) के स्थान पर लगभग क्या मान आयेगा ? 

589586 ÷ 102.014 + 87974.64 ÷ 110.20 = ? 

1. 7200 
2. 8200 
3. 8500 
4. 7500 
5. 6600 

Solutions 5 

5780 + 800 = ?

? = 6580

Q.9. In each of the following questions, two equations are given. You have to solve them and give answer.

निम्नलिखित प्रश्न में दो समीकरण I और II दिये गये है दोनों समीकरण हल कीजिए और उत्तर दीजिए 

I.

II.

1. If p > q
2. If p > q
3. If p < q
4. If p < q
5. If p = q or relationship can not be established

Solutions 1 

I.

15 + 8p = 5p

15 = – 3p

p = – 5

II.

q = - 6

Hence, p > q

Q.10. In each of the following questions, two equations are given. You have to solve them and give answer.

निम्नलिखित प्रश्नों में दो समीकरण (I) और (II) दिये गये है दोनों समीकरण हल कीजिए और उत्तर दीजिए- 

I. p² + 16p + 63 = 0

II. q² + 13q + 42 = 0 

1. If p > q
2. If p > q
3. If p < q
4. If p < q
5. If p = q or relationship can not be established

Solutions 4 

I. p² +16p + 63 = 0
   p² + 9p + 7p + 63 = 0
   p(p + 9) + 7(p + 9) = 0
   (p + 9)(p + 7) = 0
    p = –9, p = –7

II. q² +13q + 42 = 0
     q² + 7q + 6q + 42 = 0
     q(q + 7) + 6(q + 7) = 0
     (q + 7)(q + 6) = 0
     q = –7, q = –6

Hence, q > p

ANSWER KEY 

Q.1 – 3

Q.2 – 1

Q.3 –2

Q.4 –4

Q.5 –3

Q.6 –4

Q.7 –5

Q.8 –5

Q.9 –1

Q.10 –4