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तीन प्रकार की दाले जिनके भारो का अनुपात 4 : 5 : 8. यदि 5 किलोग्राम पहली प्रकार की दाल , 10 किलोग्राम की दूसरी दाल और कुछ मात्र की तीसरी दाल मिले जाती है तो भार का अनुपात 5 : 7 : 9 . हो जाता है तीसरी मिलाये गए दाल की मात्रा ज्ञात कीजिये?
(A) 42
(B) 48
(C) 40
(D) 45
Q2.) A person started his journey in the morning. At 11.a.m he covered
एक व्यक्ति अपनी यात्रा सुबह प्रारम्भ करता है 11 बजे तक वह अपनी यात्रा का 3/8 हिस्सा तय करता है और शाम को 4.30 तक वह अपनी यात्रा का 5 /6 हिस्सा पूरा करता है तो उसने यात्रा कितने बजे प्रारम्भ की ?
(A) 6.00 a.m.
(B) 3.30 a.m.
(C) 7.00 a.m.
(D) 6.30 a.m.
Q3.) A person can row
एक व्यक्ति की चाल शांत जल में
(A) 2 km/h
(B) 3 km/h
(C) 2.5 km/h
(D) 3.5 km/h
Q4.) A contractor undertake to finish a certain work in 124 days and employed 120 men. After 64 days, he found that he had already done 2/3 of the work. How many men can be discharged so that the work may finish in time ?
एक ठेकेदार ने 124 दिनों में किसी काम को पूरा करने का ठेका लिया। उसने 120 व्यक्ति कार्य पर लगाये परन्तु 64 दिन में 2 /3 कार्य ही हो पाया तो कितने व्यक्ति को हटाया जाये की कार्य समय पर समाप्त हो जाये?
(A) 50
(B) 48
(C) 56
(D) 64
Q5.) At each corner of a triangular field of sides 26m, 28m, and 30m, a cow is tethered by a rope of length 7m. the area ungrazed by the cow?
एक त्रिभुज जिसकी भुजाये 26m, 28m, and 30m है गाय को तीनो कोनो में बंधा जाता है तो गाय कितना हिस्सा नहीं खा सकती है ?
(A) 336
(B) 259
(C) 154
(D) 77
Q6.)
(A)
(B) 4
(C) -4
(D)
Q7.) If
यदि
(A)
(B)
(C)
(D)
Q8.) If
यदि
(A)
(B)
(C)
(D)
Q9.) Simplify it
(A) 44
(B) 32
(C) 100
(D) 24
Q10.) What is the unit digit
(A) 4
(B) 0
(C) 6
(D) 5
ANSWERS:
Q.1 (D)
Let the ratio of initial quantity be x i.e
So,
On solving (i) and (ii) we get
So a = 45 kg
Q.2 (D)
Difference of time = 4.30 p.m. – 11.a.m. =
Distance covered in
Clearly the person started at 6.30 a.m.
Q.3 (C)
Let the speed of stream be
Speed of upstream =
Speed in downstream =
Then,
Q.4 (C)
Days remaining 124 – 64 =60 days
Remaining work = 1-
So men required =
Men discharge = 120 – 64 = 56 men
Q.5 (B) Area grazed by all cows
Area of the triangle formed be the sides
Semi perimeter = 26+28+30+/2= 42m
=
=
Q.6 (B)
=
S0
Q.7 (D)
b = p-1, h=p+1
P = 2
Q.8 (B)
Q.9 (C)
We know that,
Q.10 (C)
Required unit digit is
Unit digit of
Unit digit of
Unit digit of
So unit digit will be 5 + 9 + 2 = 6.