SSC CHSL Quiz : Quantitative Aptitude | 12 - 03 - 18

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Q1.) A metal pipe is 21 cm long and its exterior diameter is 8cm. If the thickness of the pipe is 1 cm and 1 cm3 of metal weight 8 g. Then metal weight of the pipe (in kg) is (use π= 22/7)

एक धातु के पाइप की लम्बाई 21 सेमी और उसका वाह्य व्यास 8 सेमी. है। यदि पाइप की मोटाई 1 सेमी है और 1 सेमी.3 धातु का भार 8 ग्राम है तो धातु के पाइप का भार है। ( π= 22/7)

(A) 3.696         

(B) 33.669       

(C) 3.966         

(D) 3.699

Q2.) What is the length of the uniform wire of diameter 0.2cm that can be drawn from a solid sphere of radius 3 cm?

3 सेमी त्रिज्या वाले धातु के एक ठोस गोले से 0.2 सेमी व्यास वाला कितने मीटर लम्बा तार बनाया जा सकता है।

(A) 72 m          

(B) 343 m        

(C) 36 m         
 
(D) 18 m

Q3.) If 3 sin x + 5 cos x = 5 then what is the value of (3cos x - 5 sin x) is.

यदि 3 sin x + 5 cos x = 5 तो (3cos x - 5 sin x) का मान क्या है।

(A) 0               
 
(B) 2       
        
(C) 3      
         
(D) 5

Q4.) The value of tan 10, tan 20, tan 40----- tan 880 tan 890 is-

10, tan 20, tan 40----- tan 880 tan 890 का मान है-

(A)

(B)          
      
(C) 1               

(D)

Q5.) Same quantity of rice is required for each member of a family of 25 members. On a particular day, due to the absence of some members of the family, the consumption of rice was reduced in the ratio 5 : 3 . the number of members absent on that day was?

चावल का एक ही मात्रा 25 सदस्यों के एक परिवार के प्रत्येक सदस्य के लिए आवश्यक है। एक विशेष दिन पर, परिवार के कुछ सदस्यों की अनुपस्थिति के कारण, चावल की खपत का अनुपात 5 : 3 में कम हो गया था। उस दिन अनुपस्थित सदस्यों की संख्या थी?

(A)3               

(B) 9     
          
(C) 15    
                      
 (D) 8

Q6.) In 40 litres of milk and water the ratio of milk to water is 7 : 1.  To get a new mixture containing milk and water in the ratio 3 : 1, the quantity of water that should be added to the mixture? 

40 लीटर के मिश्रण दूध पानी का अनुपात 7 : 1 है कितना पानी और मिलाया जाये की नए वाले मिश्रण में  दूध पानी का अनुपात 3 : 1 हो जाये ?

1. 6                 
2.                
3.                

Q7.)  600 amount to Rs. 740 in 5 years at a certain rate of simple interest. If the rate of interest is increased by 3 % . what will be the amount then ?

600 रुपए की राशि 5 वर्षो में 740 हो जाती है यदि ब्याज की दर को 3 % बढ़ाया जाता है तो अब राशि ज्ञात कीजिये

(A) 800                        
(B) 856            
(C) 930            
(D) 830

Q8.) A car run one kilometer in 4 minutes 54 seconds and B can run this distance in 5 minutes. At the start of one kilometer race, B should stand how much ahead of A, so that both of them reach the finish point together?

A एक किलोमीटर की दूरी 4 मिनट 54 सेकण्ड तथा B यह दूरी 5 मिनट में दौड़ सकता है। किसी एक किलोमीटर की दौड़ में B को A से कितना आगे खड़ा किया जाए ताकि वे दोनों समाप्ति बिन्दु पर एक साथ पहुँचे?

(A) 20 meter 
(B) 16 meter          
(C) 18 meter          
(D) 14.15 meter

Q9.) If then

          यदि तो

(A) 45.45     
(B) 56.56      
(C) 67.67      
(D) 78.78

Q10.) A man marks his goods at a price that would give him 20% profit. He sells 3/ 5 of the goods at the marked price and the remaining at 20% discount. What is his gain percent on the whole 
transaction?

एक व्यक्ति अपनी वस्तुओं को इस प्रकार अंकित करता है उसे 20% का लाभ हो। वह 3/ 5 वस्तुएं अंकित कीमत पर बेचता है और शेष 20% छूट (बट्टे) पर। सारे सौदे में उसका प्रतिशत लाभ क्या है?

(A) 15%       
(B) 12%       
(C) 10.4%    
(D) 8%





Answer:

1.(A)

External radius of pipe r2 = 4 cm
 Internal radius = r1 = 4 - 1 = 3 cm.
 volume of pipe = (r22 - r21) ×h.
= π (16 - 9) × 21 = 22/7 × 7 × 21 = 462 cu.cm.
Weight of pipe = volume × Density.
= 3.696 kg.

2. (C)

Radius of sphere r = 3 cm = 0.3 m
 and diameter of wire = 0.2 cm
 So Radius = 0.1 cm = 0.001 m
 Volume of sphere = Volume of wire.
 

3.(C)

3sinx + 5cosx = 5
9sin²x + 25cos²x + 30 sinx cosx = 25
9(1-cos²x)+25(1-sin²x)+30 sinx cosx = 25
9+25-(9cos²x+25sin²x-30sinx cosx) = 25
9 = (3 cosx - 5 sinx)²
3 cos x - 5 sin x = 3

4.(C)

(tan 10- tan 890) (tan 20 - tan 880) ----- tan 450
= (tan 10 cot 10) (tan 20 cot 20) ---- tan 450 = 1
[tan (900-θ) = cot θ],   [cot (900 -θ) = tan θ]
 tan θ. cotθ = 1

5.(C)

given ratio 
total members : absent = 5 : 3
Hence, number of person absent =  25 = 15

6.(C)

In a 40 litre of mixture,
         Quantity of water is =
         Quantity of milk =
        
        
                                     

7.(D)

New amount = original amount + extra interest
Extra interest due to increment of 2 % rate of interest =
Rs. 830

8.(A)

Let B stand ahead of A = x meter

1000 – x = 980
x = 20 m.

9.(B)

= 3 × + 5 ×  + 7 × + 25 ×
= 40 × = 40 × 1.414 = 56.56

10.(C)

Let the C.P. of 1 article be Rs.100
M.P. = Rs120
S.P. = x × 120 + x × × 120
=
Rs.
P% =