Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concepts of all the topics so that you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern so that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.
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Q.1–3: What value will come in place of question mark (?) in the following number series?
निम्नलिखित संख्या श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आयेगा ?
Q1: 256 137 ? 1353 12705 131761.5
(1) 226
(2) 220
(3) 230
(4) 236
(5) 240
Q2: 9 9 18 36 ? 288
(1) 72
(2) 36
(3) 144
(4) 180
(5) 18
Q3: 5 10 ? 160 785 3910
(1) 20
(2) 25
(3) 15
(4) 35
(5) 30
Q4: A shopkeeper marks his goods at such a price that he can deduct 15% for cash and yet make 20% profit. Find the marked price of an item which costs him Rs.405.
एक दुकानदार अपने सामान को इस मूल्य पर अंकित करता है कि नकद भुगतान करने पर वह 15% की छूट देने के बाद भी 20% का लाभ प्राप्त करता है | एक वस्तु का अंकित मूल्य ज्ञात कीजिये जिसकी लागत उसके लिए 405 रु. है |
(1) Rs. /रु.
(2) Rs. /रु.
(3) Rs. /रु.
(4) Rs. /रु.
(5) None of these/इनमें से कोई नहीं
Q5: The difference in simple interest and compound interest on a certain sum of money in 3 years at 15% p.a. is Rs.453.6. The sum is
एक निश्चित धनराशि पर 3 वर्ष में 15% वार्षिक ब्याज की दर से साधारण ब्याज और चक्रवृद्धि ब्याज में अन्तर 453.6 रु. है | धनराशि है
(1) Rs. /रु.6000
(2) Rs. /रु.6200
(3) Rs. /रु.6300
(4) Rs. /रु.6400
(5) None of these/इनमें से कोई नहीं
Q6: The average of present ages of five persons is 29.2. Among them, the sum of the present age of a girl and brother including her teacher is 11 years more than the average of the present ages of her parents. Find the sum of the present age of the girl and her teacher if it is given that her brother will be of 22 years after 5 years.
पांच व्यक्तियों की वर्तमान औसत आयु 29.2 है | उनमें से, एक लड़की और उसके भाई और उसके अध्यापक की वर्तमान आयु का योग उसके माता – पिता की औसत आयु से 11 वर्ष अधिक है | लड़की और उसके अध्यापक की वर्तमान आयु का योग ज्ञात कीजिये जबकि यह ज्ञात है कि उसका भाई अब से 5 वर्ष बाद 22 वर्ष का हो जाएगा ?
(1) 40 years/वर्ष
(2) 41 years/वर्ष
(3) 39 years/वर्ष
(4) 45 years/वर्ष
(5) Cannot be determined/निर्धारित नहीं किया जा सकता है |
Q7–8: What value will come in place of question mark (?) in the following question?
निम्नलिखित प्रश्न में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आयेगा ?
Q7: 420 × 276 + 315 × 256 + 630 × 216 + 420 × 408 = ?
(1) 5040
(2) 25600
(3) 504000
(4) 50400
(5) 540000
Q8: (24)2
+ (17)2 – (22)2 – (17)3 + (18)3 = ?
(1) 1200
(2) 1250
(3) 1500
(4) 1350
(5) 1300
Q. (9–10): In these questions, two equations numbered I and II are given. You have to solve both the equations and give answer:
इन प्रश्नों में, I और II संख्यांकित दो समीकरण दिए गए हैं। आपको समीकरणों को हल करना होगा और जवाब देना होगा:
(1) If/यदि p > q (2) If/यदि p > q
(3) If/यदि p < q
(4) If/यदि p < q
(5) If/यदि p = q or relationship between p and q cannot be established/या p और q के मध्य सम्बन्ध स्थापित नहीं किया जा सकता है ।
Q9: I. 2p2 – 11p + 15 = 0 II. 2q2 – 15q
+ 28 = 0
Q10: I. 3p2 – 10p + 3 = 0 II. q2 – 5q
+ 6 = 0
ANSWER KEY:
Q1. (4) × 0.5 + 9, × 1 + 99, × 1.5 + 999, × 2 + 9999, × 2.5 + 99999
Q2. (3) × (3 – 2), × (5 – 3), × (7 – 5), × (11 – 7), × (13 – 11)
Q3. (4) + 51, + 52, + 53, + 54,
+ 55
Q4. (3) Required marked price/अभीष्ट अंकित मूल्य = 405 = Rs. /रु.
Q5. (4) Required sum/अभीष्ट धनराशि =
=
= Rs. /रु.6400
Q6. (3) A + B + T + M + F = 146 … (i)
A + B + T = … (ii)
From (i) and (ii), we get/(i) और (ii) से हम प्राप्त करते हैं,
+ D + E = 146
= 45
From (i), we get/(i) से हम प्राप्त करते हैं, A + T = 146 – 90 – 17 = 39 years/वर्ष
Q7. (3) 420 × 276 + 315 × 256 + 630 × 216 + 420 × 408 = ?
? = 5040 × 23 + 5040 × 16 + 5040 × 27 + 5040 × 34
? = 5040 × 100
? = 504000
Q8. (5) (24)2
+ (17)2 – (22)2 – (17)3 + (18)3 = ?
576 + 289 – 484 – 4913 +
5832 = ?
? = 6697 – 5397
? = 1300
Q9. (4) I. 2p2 – 11p + 15 = 0
2p2 – 6p – 5p + 15 = 0
2p (p – 3) – 5(p – 3) = 0
(2p – 5) (p – 3) = 0
p = 5/ 2, 3
II. 2q2 – 15q + 28 = 0
2q2 – 8q – 7q + 28 = 0
2q (q – 4) – 7(q – 4) = 0
(2q – 7) (q – 4) = 0
q = 7/2, 4
2p (p – 3) – 5(p – 3) = 0
(2p – 5) (p – 3) = 0
p = 5/ 2, 3
II. 2q2 – 15q + 28 = 0
2q2 – 8q – 7q + 28 = 0
2q (q – 4) – 7(q – 4) = 0
(2q – 7) (q – 4) = 0
q = 7/2, 4
Hence/ अतः
p < q.
Q10. (3)
I. 3p2 – 10p + 3 = 0
3p2 – 9p – p + 3 = 0
3p (p – 3) – 1 (p – 3) = 0
(3p – 1) (p – 3) = 0
p = 1/ 3, 3
II. q2 – 5q + 6 = 0
q2 – 2q – 3q + 6 = 0
q (q – 2) – 3(q – 2) = 0
(q – 2) (q – 3) = 0
q = 2, 3
3p2 – 9p – p + 3 = 0
3p (p – 3) – 1 (p – 3) = 0
(3p – 1) (p – 3) = 0
p = 1/ 3, 3
II. q2 – 5q + 6 = 0
q2 – 2q – 3q + 6 = 0
q (q – 2) – 3(q – 2) = 0
(q – 2) (q – 3) = 0
q = 2, 3
Hence/अतः,
p < q