Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concepts of all the topics so that you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern so that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.
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Q1. The population of a village was 20000. After two years population became 22050, what was growth rate per year?
एक गांव की जनसंख्या 20000 थी। दो वर्ष बाद जनसंख्या 22050 हो गई तो प्रति वर्ष जनवंख्या वृद्धि दर क्या थी?
(1) 5 (2) 10 (3) 12 (4) 15 (5) 18
Q2. Father's age is five times the son's age. After 8 years father's age will be thrice the son's age. What is father's present age?
पिता की आयु पुत्र की आयु की पाँच गुनी है। 8 वर्ष बाद पिता की आयु पुत्र की आयु की तीन गुना होगी। पिता की वर्तमान आयु क्या है?
(1) 35 (2) 40 (3) 45 (4) 50 (5) None of these
Q3. In what time a 360 m. long train moving at the speed of 45 km/hr will cross a 140 m. long bridge?
360 मी. लम्बी एक ट्रेन 45 किमी./घं. की चाल से चलते हुए 140 मी. लम्बे पुल को कितने समय में पार करेगी?
(1) 30 (2) 35 (3) 40 (4) 45 (5) 50
Q4. The breadth of a rectangular field is 75% of its length. If perimeter of the field is 1050 m, what will be the area of field?
एक आयताकार खेत की चौड़ाई उसकी लम्बाई की 75% है। यदि खेत का परिमाप 1050 मी. हो तो खेत का क्षेत्रफल क्या होगा?
(1) 67250 (2) 67500 (3) 66250 (4) 66500 (5) 65500
Q5. The difference between circumference and semi diameter of a circle is 37 cm. What is the diameter of the circle?
एक वृत्त की परिधि और अर्द्धव्यास का अन्तर 37 सेमी. है। वृत्त का व्यास क्या है?
(1) 35 (2) 28 (3) 21 (4) 14 (5) 7
Q6. If the average of 5 consecutive odd numbers is 31.What is sum of the largest and the smallest odd number –
यदि 5 लगातार विषम संख्याओं का औसत 31 है तो सबसे बड़ी तथा सबसे छोटी विषम संख्या का योग कितना होगा?
(1) 31 (2) 29 (3) 27 (4) 25 (5) 23
Q7. What will be profit percent, if selling price is 1.5 times of cost price?
यदि विक्रय मूल्य क्रय मूल्य का 1.5 गुना हो तो, लाभ प्रतिशत कितना होगा?
(1) 72% (2)75% (3) 60% (4) 50% (5) 45%
Q8. If the difference between C.I and S.I on Rs. 3516 is 35.16 for two years. What was rate of interest?
यदि 3516 रू. पर दो वर्षों का चक्रवृद्धि ब्याज तथा साधारण ब्याज का अन्तर 35.16 है तो ब्याज दर क्या होगी?
(1) 5% (2)10% (3) 15% (4) 20% (5) 25%
Q9. Find compound interest on Rs. 3000 for two years at rate of 5% per annum?
3000 रू. पर 5% वार्षिक ब्याज की दर से 2 वर्षों का चक्रवृद्धि ब्याज क्या होगा?
(1) 157.5 (2) 156.5 (3) 155.5 (4) 154.5 (5) 153.5
Q10. If the ratio of work efficiency of A and B is 3 : 2.If A and B together finish a work in 5 days in how many days B alone complete the work?
A और B की कार्य करने की क्षमता का अनुपात 3 : 2 है, यदि किसी काम को A और B साथ मिलकर 5 में समाप्त करते हैं तो B अकेले उसी काम को कितने दिन में समाप्त करेगा?
(1) 8 (2) 8.5 (3) 10 (4) 12 (5) 12.5
Answer Key-
Q1. (1)
r = 5%
Q2. (2)
F = 5S_________(I)
(F+8) = 3(S+8)
F+8 = 3S+24
F – 3S = 16 _________(II)
From equation (I) and (II),
S = 8 years
F = 40 years
Q3. (3)
Q4. (2)
b = l ×
__________(I)
__________(I)
2(l+b) = 1050
l+b = 525___________(II)
From equation (I) and (II),
l = 300m, b = 225 m
Area = l × b
= 300 × 225
= 67500 m2.
Q5. (4)
Diameter = 7×2 = 14 cm.
Q6. (3)
Let odd numbers are x, x+2, x+4, x+6, x+8
= 31
x = 27
Q7. (4)
Q8. (2)
Q9. (1)
Q10. (5)
Ratio of work efficiency of A and B = 3 : 2
(A+B)'s one day work = 5
total work = 5 × 5 = 25
B alone can do in = 
