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Q.1. If 2cos2A + 3cosA = 2, then 4sin4A+ 9sin2A = ?
यदि 2cos2A + 3cosA = 2 है, तो 4sin4A+ 9sin2A = ?
(A) 3
(B) 3/4
(C) 9
(D) 9/4
Q.2. If sin A = 3/4 then find the value of tan2A – sec2A – 3sin2A+ 2cos2A.
यदि sin A =3/4, तो tan2A– sec2A – 3sin2A+ 2cos2A का मान ज्ञात कीजिये ?
(A) – 4/5
(B) 4/5
(C) – 13/16
(D) – 29/16
Q.3. If / यदि
, 
. Then find the value of a2 + b2 + ab/तो a2 + b2 + ab का मान ज्ञात कीजिये ।
, . Then find the value of a2 + b2 + ab/तो a2 + b2 + ab का मान ज्ञात कीजिये ।
(A) 194
(B) 119
(C) 195
(D) 227
Q.4. A wire is in the form of a circle enclosing an area of 1386 cm2. If the same wire is bent into the form of a circle, then find the area of that circle.
एक तार 1386 सेमी2 के एक क्षेत्र के चारों ओर वृताकार तारबंदी के रूप में है। यदि इस तार को वृत्त के रूप में मोड़ा जाये, तो उस वृत्त का क्षेत्रफल ज्ञात कीजिये ।
(A) 512 cm2/सेमी2
(B) 589 cm2/सेमी2
(C) 1089 cm2/सेमी2
(D) 739 cm2/सेमी2
Q.5. The percentage profit earned by selling an article for Rs.1800 is equal to the percentage loss incurred by selling the same article at Rs.1400. At what price should the article be sold to make a profit of 35%.
एक वस्तु को 1800 रू. में बेचने पर हुआ लाभ 1400 रू. में बेचने पर हुई हानि के बराबर है। तो 35% लाभ प्राप्त करने के लिए वस्तु का विक्रय मूल्य कितना होगा?
(A) Rs.2060
(B) Rs.2760
(C) Rs.2160
(D) Rs.2560
Q.6. A boat goes 96 km in upstream and return back 32 km in downstream and takes 14 hours to complete the journey. If the speed of boat in upstream is 8 km/hr. Then find the ratio of speed of boat in still water and speed of stream.
एक नाव धारा के विरूद्ध 96 किमी जाती है तथा धारा के साथ वापस 32 किमी आती है, इस प्रकार कुल यात्रा में 14 घण्टे लगते हैं । यदि धारा के विरूद्ध नाव की चाल 8 किमी/घंटा है तो शान्त जल में नाव की चाल तथा धारा की चाल का अनुपात ज्ञात कीजिये ।
(A) 3: 1
(B) 2: 1
(C) 4: 1
(D) 5: 3
Q.7. If A sec 30. cos 60 = B cot 45. cosec 45 then find the ratio A: B = ?
यदि A sec 30. cos 60 = B cot 45. cosec 45 तो A: B = ?
(A) 1: 
(B) 
(C) 
(D) 
Q.8. A largest possible cone is cut from a cube of volume 1728 m3. The volume of cone is:
एक घन जिसका आयतन 1728 मी3 है, उससे एक सबसे बड़ा संभव शंकु काटा जाता है। शंकु का आयतन क्या होगा ?
(A) 188
(B) 140
(C) 144
(D) 248
Q.9. If 
the find the value of
?
the find the value of ?
यदि 
तो 
का मान ज्ञात कीजिए।
तो का मान ज्ञात कीजिए।
(A) 96
(B) 200
(C) 207
(D) 198
Q.10. The sum of a two digit number and the number formed by reversing its digit is a perfect square. What is the sum of the digit of the number?
दो अंकों वाली संख्या और उसके अंकों को उलटकर मिलने वाली संख्या का योग एक पूर्णवर्ग है । संख्या के अंकों का योग क्या है ?
(A) 13
(B) 11
(C) 15
(D) Can't be determined/ज्ञात नहीं किया जा सकता
ANSWER KEY:
Q1. (C) 2cos2A + 3cosA = 2, then 4sin4A+ 9sin2A = ?
3cosA = 2(1 – cos2A)
3cos A = 2sin2A (squaring both sides/ दोनो तरफ वर्ग करने पर)
9cos2A = 4 sin4A
9(1 - sin2A) = 4 sin4A
then/तो,
4sin4A+ 9sin2A = 9
Q2. (D) sin A = 3/4
(tan2A – sec2A) – 3sin2A+ 2cos2A.
= – 1 × 3 × (3/4)2 + 2 – 2(3/4)2= – 29/16
Q3. (C)
, 
,
a = 7 + 4√3 a2 = 97 + 56√3
b = 7 - 4√3 b2 = 97 - 56√3
Then/तो, a2 + b2 + ab = 97 + 56√3 + 97 – 56√3 + 1 = 195
Q4. (C) 1089 cm2/सेमी2
Q5. (C) Let profit = Loss = x
माना लाभ = हानि = x
Then/तो,
1800 – x = x – 1400
x = 200
C.P./क्रय मूल्य = 1400 + 200 = 1600
S.P./विक्रय मूल्य = 
= Rs.2160
= Rs.2160
Q6. (A) 
x + y = 16
x – y = 8
x = 12
y = 4
Required ratio/अभीष्ट अनुपात = 12: 4 = 3: 1
Q7. (D) 
A: B = 
Q8. (C) Volume/आयतन = 
= 144
= 144
Q9. (D) 
Q10. (B) (10x + y) + (10y + x) = 11(x + y)
Then/तो (x + y) = 11
For perfect square/पूर्ण वर्ग के लिए
