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Quantitative Aptitude Questions For IBPS Clerk Mains | 06- 01 - 19

Mahendra Guru
Quantitative Aptitude Questions For IBPS Clerk Mains | 06- 01 - 19
Dear Aspirants,

As IBPS has released the official notification of the Common Recruitment Process for selection of personnel for Clerical cadre Posts and the exam is tentatively scheduled to be held December 2018 & January 2019. Looking at the notification, we have now started subject-wise quizzes for the exam. It will include quizzes of all the subjects- Quantitative Aptitude, English, Reasoning and Computer. All these quizzes will be strictly based on the latest pattern of the IBPS Clerk exam and will be beneficial for your preparations. So, keep following the quizzes which will provide you a set of 10 questions daily.
Here, we are providing you important questions of Quantitative Aptitude for IBPS Clerk 2018 exam.

Q1-5. What value will come in place of question mark (?) in the questions given below?

निम्नलिखित प्रश्नों में प्रश्नवाचक चिन्ह ( ?) के स्थान पर क्या मान आयेगा ?

Q1. 188×18×8-8088 = ?
(1) 18984 
(2) 19022 
(3) 18816 
(4) 18626 
(5) 18920 

Q2. 64% of 842 – ?% of 426 =334.4
(1) 34 
(2) 38 
(3) 42 
(4) 46 
(5) 48 

Q3. 9984 ÷ = 384 
(1) 636 
(2) 646 
(3) 656 
(4) 666 
(5) 676 

Q4. (16)3- (16)2 = ?
(1) 3840 
(2) 3620 
(3) 3710 
(4) 3550 
(5) 3320 

Q5. 26831 + 8348 - 2061 = ? × 58
(1) 569 
(2) 573 
(3) 575 
(4) 571 
(5) 582 

Q6-10. In each of the following questions, two equations (I) and (II) are given. You have to solve them and Give answer-

निम्नलिखित प्रश्नों में दो समीकरण (I) और (II) दिये गये है दोनों समीकरण हल कीजिए और - उत्तर दीजिए 

Q6. (I) 10x2 -33x +27 = 0               (II) 18y2 - 17y +4 = 0
(1) x > y 
(2) x > y 
(3) x < y 
(4) x < y 
(5) x = y or relationship cannot be established 

Q7. (I) 2x2 + 5x - 12 = 0                  (II) 2y2 + 5y - 7 = 0
(1) x > y 
(2) x > y 
(3) x < y 
(4) x < y 
(5) x = y or relationship cannot be established 

Q8. (I) 2x2 + 9x + 10 = 0                (II) 2y2 + 17y + 30 = 0
(1) x > y 
(2) x > y 
(3) x < y 
(4) x < y 
(5) x = y or relationship cannot be established 

Q9. (I) 17x - 57 = 300 -4x             (II) y =
(1) x > y 
(2) x > y 
(3) x < y 
(4) x < y 
(5) x = y or relationship cannot be established 

Q10. (I) 6x2- 19x + 15 = 0               (II) 4y2 -16y + 15 = 0
(1) x > y 
(2) x > y 
(3) x < y 
(4) x < y 
(5) x = y or relationship cannot be established 

Answer Key-
Q1. (1) 
? = 27072 – 8088 = 18984

Q2. (5)

Q3. (5)

Q4. (1)
? = 4096 – 256 = 3840

Q5. (4)

Q6. (1)
(I) 10x2-15x-18x+27 = 0

5x(2x - 3) -9(2x-3) = 0
x = ,

(II) 18y2 - 9y -8y+4 = 0
9y(2y-1) -4(2y-1) = 0
y = ,
> y

Q7. (5)
(I) 2x2 +8x -3x-12 = 0
2x(x+4) -3(x+4) = 0
x = ,-4

(II) 2y2 +7y-2y-7 =0
y(2y+7)-1(2y+7) = 0
y = 1,
So relationship can not be set up.

Q8. (2)
(I) 2x2 + 4x +5x+ 10 = 0
2x(x+2) +5 (x+2) = 0
x = ,-2

(II) 2y2 + 12y + 5y +30 = 0
2y(y+6) +5(y+6) = 0
y = -6,
> y

Q9. (5)
(I) 17x + 4x = 357
21x = 357
x = 17

(II) y = 17
x = y

Q10. (5)
(I) 6x2 - 10x -9x +15 = 0
2x(3x-5) -3(3x-5) = 0
x =

(II) 4y2 - 10y -6y +15 = 0
2y(2y-5) -3(2y-5) = 0
y =
So, relation can't be established.

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