Quantitative Aptitude Questions For SBI Clerk : 12 - 02 - 18

Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concept of all the topic so you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern. So that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.

Mahendra Guru provides you a Bank Quiz of Quantitative Aptitude on daily basis to help you in your preparation for Govt job. You can clear your doubts before an exam. Mahendra Guru also provides you an important note and study material for all subject and test through its website, Mahendra Guru App and YouTube channel apart from it Speed Test Portal. Most of these preparation products are also available for purchase on my shop. You can also visit Mahendras.org to get more information about our endeavour for your success. You can also study in details through our E-Mahendras Facebook andMahendra Guru YouTube channel of Quantitative Aptitude.

Q.1 Sum of three consecutive odd numbers and three consecutive even number is 231. If the smallest odd number is 11 less then the smallest even number than find the sum of largest odd number and largest even number

तीन क्रमिक विषम संख्याओं और तीन क्रमिक सम संख्याओं का योग 231 है। यदि सबसे छोटी विषम संख्या सबसे छोटी सम संख्या से 11 कम है तो सबसे बड़ी विषम संख्या और सबसे बड़ी सम संख्या का योग ज्ञात कीजिए?

1. 83
2. 85
3. 79
4. 87
5. None of these

Q.2 In two vessels ratio of milk and water is 5:3 and 5:7 respectively. They are mixed together in 5:4 . Find the ratio off milk and water in the final mixture.

दो पात्रों में दूध तथा पानी का अनुपात क्रमशः 5 : 3 तथा 5 : 7 है। इन्हें 5 : 4 के अनुपात में मिलाया जाता है। अन्तिम मिश्रण में दूध तथा पानी का अनुपात ज्ञात कीजिये।

1. 77 : 63
2. 101 : 91
3. 107 : 93
4. 115 : 101
5. None of these

Q.3 The sum of salary of three persons A,B and C is Rs. 72000. They spend 80, 85 and 75 percent of their salary respectively. If ratio of their savings is 8 : 9 : 20, what is A’s salary?

तीन व्यक्ति A,B और C जिनके वेतन का योग 72000 रूपये है, क्रमशः अपने वेतन का 80, 85 और 75 प्रतिशत खर्च कर देते हैं। यदि उनकी बचतों का अनुपात 8 : 9 : 20 हो तो A का वेतन कितना है?

1. 15000
2. 16000
3. 12000
4. 17500
5. Can not be determined

Q.4 The simple interest accrued on an amount of Rs. 8500 at the end of four years is Rs.3400. What would be the compound interest accrued on the same amount at the same rate of interest after three years?

8500 रुपये की राशि पर चार वर्ष के अंत में अर्जित साधारण ब्याज  3500 रुपये है । तीन वर्ष पश्चात उसी ब्याज दर  पर समान राशि पर अर्जित चक्रवृद्धि ब्याज क्या होगा? 

1. 2348.50 Rs
2. 3214 Rs
3. 2813.50 Rs
4. 2640.25 Rs
5. 2720.75 Rs

Q.5 Anita purchased one table and one chair costing Rs. 680 and Rs. 585 respectively. If she sells table at a loss of  20/3% and chair at a profit of  50/3% . Find the total amount she will get by selling these articles?

अनीता ने एक मेज तथा एक कुर्सी खरीदी जिनकी कीमत क्रमशः 680 रूपये तथा 585 रूपये हैं। यदि मेज पर उसे 20/3%  की हानि हुई तथा कुर्सी पर 50/3% का लाभ हुआ तो वह इन वस्तुओ को बेच कर कितना धन प्राप्त करेगी ज्ञात कीजिये ?

1. 1280 Rs
2. 1296 Rs.
3. 1440 Rs
4. 1320 Rs
5. None of these

Q.6 The ratio of present ages of D and S is 3 : 5 respectively. 5 years ago the ratio of their ages was 10 : 25 respectively. What will be S's age after 7 years?

D और S की वर्तमान आयु का अनुपात क्रमशः 3 : 5 है । 5 वर्ष पूर्व उनकी आयु का अनुपात क्रमशः 10 : 25 था । 7 वर्ष बाद S की आयु क्या होगी?

1. 18 years
2. 22 years
3. 19 years
4. 27 years
5. 23 years

Q.7 What approximate value will come at place of question mark (?) in the following question?

निम्नलिखित प्रश्न में प्रश्नवाचक चिन्ह (?) के स्थान पर लगभग क्या मान आयेगा?

71.97% of 143.02 + 212.04% of 108.11 = ? % of 298.76

1. 98
2. 110
3. 118
4. 132
5. 124

Q.8 The simple interest accured on an amount of Rs. 40,000 at the end of three years is Rs. 12,000. What would be the compound interest accured on the same amount at the same rate in the same period?

40,000 रू पर तीन वर्षों में मिलने वाला साधारण ब्याज 1200 रू. हैं। समान धनराशि पर समान ब्याज दर से समान वर्षों में कितना चक्रवृद्धि ब्याज मिलेगा? Rs.13000 Rs.13310 Rs.13240 Rs.12860 Rs.1286 Q.9 The ratio of the present ages of Subhi and her mother is 1 : 2. The ratio will become 10 : 19 after 3 years. What is the difference in their age? शुभी और उसकी माँ की वर्तमान आयु का अनुपात 1 : 2 है। 3 वर्ष बाद यह अनुपात 10 : 19 हो जायेगा। उनकी आयु का अंतर ज्ञात कीजिये 33 30 27 24 21 Q.10 A train travels a distance of 384 km at an average speed of 160 km/h from station A to station B. It then travels back to A taking 5 h 36 min. Find the average speed of the train on the return journey to A. एक ट्रेन स्टेशन A से स्टेशन B तक 384 किमी. की एक दूरी को 160 किमी./घंटा की औसत चाल से तय करती है | यह फिर वापस A की ओर 5 घंटे 36 मिनट में तय करती है | वापस A की ओर यात्रा करने में ट्रेन की औसत चाल ज्ञात कीजिये | 96 kmph 84 kmph 92 kmph 90 kmph None of these

SOLUTIONS DETAIL
ANS – 1

Let the smallest odd number be x
Let the smallest even number be y
Given, y - x = 11 ...........(i)
(x + x + 2 +x + 4) + (y +y +2 +y + 4) = 231
3x + 3y = 219
x + y = 73............(ii)
On, (i) + (ii)
y = 42
x = 33
y + 4 + x + 4 = 83

ANS – 2
5 : 3 = 8 ) × 3 × 5          
5 : 7 = 12 ) × 2 × 4
75            45
40            56
115 : 101 

ANS – 3


ANS – 4


ANS – 5

ANS – 6

ANS – 7
103++229=?%of300
?=111
ANS – 8
R = 10%
C.I. = 33.1% of P = Rs.13240
ANS -  9
P0 : M0 = [1 : 2] × 9 = 9 : 18
P+3 : M+3 = [10 : 19] × 1 = 10 : 19
1 = 3
9 = 9 × 3 = 27
ANS – 10
Average speed = Total Distance / Total Time taken
Total distance = 384 + 384 = 768 km
t1 = /384/160  = 2.4 hours, t2 = 5 hours 36 minutes = 5.6 hours
Total time taken = 5.6 + 2.4 = 8 hours
Therefore, average speed = 768/8 = 96 kmph