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SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

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SSC CHSL Quiz : Quantitative Aptitude | 19 - 03 - 18

In SSC exam quantitative Aptitude section is more scoring and easy if you know the shorts tricks and formulas of all the topic. So, it is important to know the basic concept of all the topic so you can apply the short tricks and solve the question with the new concept in lesser time while giving the quiz. It will help you to score more marks from this section in less time period. Quantitative Aptitude section basically measures your mathematical and calculation approach of solving the question. SSC Quiz Of quantitative Aptitude section helps you to analysis your preparation level for upcoming SSC examination. Mahendra Guru provides you Quantitative Aptitude Quiz for SSC examination based on the latest pattern. So that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like Insurance, SSC-MTS, CGL, CHSL, State Level, and other Competitive exams.

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Q.1 If tan θ = SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18, then find the value of SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18.
यदि tan θ = SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18 है, तो SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18 का मान ज्ञात कीजिये ।

(A) 0
(B) 1
(C)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18
(D)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

Q.2 If sin2θ = SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18, then cos ( 75° – θ) is:
 यदि sin2θ = SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18  है , तो cos ( 75° – θ) है

(A)0

(B)1

(C)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

(D)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

Q.3 Find the value of x, for which equation 12 – 6x and 4x + 2 equals to.
x का वो मान ज्ञात कीजिये जिसके लिए समीकरण 12 – 6x और 4x + 2 बराबर हो ।

(A)1

(B)-1

(C)2

(D)-2
Q.4 Find the value of x, for which equation –SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18 + 2 and x – 6 are equal.
x का वो मान ज्ञात कीजिये जिसके लिए समीकरण –SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18 + 2 और x – 6 बराबर हो ।

(A)4

(B)3

(C)2

(D)1

Q.5 ΔDEF and ΔGHI are similar triangle. If length of DE is 4 cm and length of GH is 9 cm, then find the ratio of area of ΔDEF and ΔGHI.
ΔDEF और ΔGHI समरूप त्रिभुज है । यदि DE की लम्बाई 4 सेमी , GH की लम्बाई 9 सेमी है तो ΔDEF और ΔGHI के क्षेत्रफल का अनुपात ज्ञात कीजिये ।

(A)4 : 9

(B)9 : 4

(C)16 : 81
 (D)81 : 16

Q6 .0.99995 + 0.88885 + 0.77775 + 0.66665 + 0.55555 = ?

(A)3.88885

(B)3.88875

(C)3.88775

(D)3.87885

Q.7 SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18– sec 45o =?

(A)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18
(B)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18
(C)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18
(D)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

Q8 . SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18+ cot 60o =?

(A) SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18
(B)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18
(C)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18
(D)SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

Q.9 A is 40% efficient than B. B can do a piece of work in 42 days. How much time will A take to complete the same work?
A, B से 40% अधिक कार्य कुशल है । B किसी कार्य को 42 दिन में पूरा कर सकता है। A इसी कार्य को पूरा करने में कितने दिन लेगा ?

(A)40

(B)36

(C)30

(D)28

Q10 Find the other diagonal of the rhombus whose area is 60 cm2 and one diagonal is 8 cm?
60 सेमी2 क्षेत्रफल वाले समचतुर्भुज का एक विकर्ण 8 सेमी है, इसका दूसरा विकर्ण ज्ञात कीजिये ।

(A)10

(B)12

(C)16

(D)15



SOLUTIONS :

Q.1) (C)

tan θ = SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18 = SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18
SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18 SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18
= SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

Q.2) (D)

sin 2θ = SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18 = sin 30o
2θ = 30o
θ = 15o
cos ( 75° – θ) = cos (75o –15o)
cos 60o = SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

Q.3) (A)

12 – 6x = 4x + 2
10 x = 10
x = 1

Q.4) (B)

SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18 + 2 = x – 6
8 =SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18
x = 3

5.) (C)

42 : 92 = 16 : 81

6.)(B)

.99995 + 0.88885 + 0.77775 + 0.66665 + 0.55555 =3.88875

Q7.) (A)

SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

8.) (B)

SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

Q9.) (C)

SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

Q10.) (D)

SSC CHSL Quiz : Quantitative Aptitude | 20 - 03 - 18

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