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Q1. The L.C.M. of two numbers is 4 times their H.C.F. The sum of L.C.M. and H.C.F is 125. If one of the numbers is 100, then the other number is-
A) 5 B) 25 C) 100 D) 125
Q2. Inside a square PQRS, ╬ФQTR is an equilateral triangle. If RT and QS intersect at O, then ∠QOR is equal to-
рд╡рд░्рдЧ PQRS рдоें, ╬ФQTR рдПрдХ рд╕рдордмाрд╣ु рдд्рд░िрднुрдЬ рд╣ै । рдпрджि RT рдФрд░ QS рдПрдХ рджूрд╕рд░े рдХो рдмिंрджु O рдкрд░ рдоिрд▓рддे рд╣ैं, рддो ∠QOR рдмрд░ाрдмрд░ рд╣ै-
A) 60° B) 90° C) 50° D) 75°
Q3. A train passes two bridges of length 400 m and 200 m. in 50 seconds and 30 seconds respectively. The length of the train is-
рдПрдХ рдЯ्рд░ेрди рджो рдкुрд▓ों рдЬिрдирдХी рд▓рдо्рдмाрдИрдпाँ 400 рдоी. рдФрд░ 200 рдоी. рд╣ैं. рдХो 50 рд╕े. рдФрд░ 30 рд╕े. рдоें рдкाрд░ рдХрд░рддी рд╣ैं । рдЯ्рд░ेрди рдХी рд▓рдо्рдмाрдИ рд╣ै-
A) 50 B) 125 C) 100 D) 225
Q4. A borrowed Rs.1500 at 4% per annum and Rs.1400 at 5% per annum for the same period. He paid Rs.390 as total interest. Find the time for which he borrowed the sum.
A рд░ु.1500 рдХो 4% рд╡ाрд░्рд╖िрдХ рдм्рдпाрдЬ рджрд░ рд╕े рдФрд░ рд░ु.1400 рдХो 5% рд╡ाрд░्рд╖िрдХ рдм्рдпाрдЬ рджрд░ рд╕े рд╕рдоाрди рд╕рдордп рдХे рд▓िрдП рдЙрдзाрд░ рд▓ेрддा рд╣ै । рд╡рд╣ рд░ु.390 рдХुрд▓ рдм्рдпाрдЬ рдХे рд░ूрдк рдоें рдЕрджा рдХрд░рддा рд╣ै । рд╡рд╣ рд╕рдордп рдЬ्рдЮाрдд рдХीрдЬिрдпे рдЬिрд╕рдХे рд▓िрдП рдЙрд╕рдиे рдзрдирд░ाрд╢ि рдЙрдзाрд░ рд▓ी рдеी ।
A) 4.5 years/рд╡рд░्рд╖ B) 4 years/рд╡рд░्рд╖ C) 3 years/рд╡рд░्рд╖ D) 3.5 years/рд╡рд░्рд╖
Q5. The length of the common chord of two circles of radii 30 cm and 40 cm whose centers are 50 cm apart, is (in cm)-
рджो рд╡ृрдд्рддों рдЬिрдирдХी рдд्рд░िрдЬ्рдпाрдПँ 30 рд╕ेрдоी. рдФрд░ 40 рд╕ेрдоी. рд╣ैं рдФрд░ рдЬिрдирдХे рдХेंрдж्рд░ 50 рд╕ेрдоी. рдХी рджूрд░ी рдкрд░ рд╣ैं, рдХी рдЙрднрдпрдиिрд╖्рда рдЬीрд╡ा рдХी рд▓рдо्рдмाрдИ рд╣ै (рд╕ेрдоी. рдоें)-
A) 48 B) 26 C) 24 D) 16
Q6. A sum of money was lent at 10% per annum, compounded annually, for 2 years. If the interest was compounded half - yearly, he would have received Rs.660.75 more. Find the sum.
рдПрдХ рдиिрд╢्рдЪिрдд рдзрдирд░ाрд╢ि рдХो 10% рдм्рдпाрдЬ рджрд░ рдкрд░ 2 рд╡рд░्рд╖ों рдХे рд▓िрдП рдЙрдзाрд░ рджिрдпा рдЬाрддा рд╣ै । рдпрджि рдм्рдпाрдЬ рдЕрд░्рдж्рдзрд╡ाрд░्рд╖िрдХ рдм्рдпाрдЬ рдХी рджрд░ рд╕े рд▓рдЧाрдпा рдЬाрдп, рддो рд╡рд╣ рд░ु.660.75 рдЕрдзिрдХ рдк्рд░ाрдк्рдд рдХрд░рддा рд╣ै । рдзрдирд░ाрд╢ि рдЬ्рдЮाрдд рдХीрдЬिрдпे ।
A) 104400 B) 150000 C) 120000 D) 124000
Q7. In a polygon, the sum of the interior angles is double the sum of the exterior angles .What is the number of sides of polygon?
рдПрдХ рдмрд╣ुрднुрдЬ рдоें, рдЖंрддрд░िрдХ рдХोрдгों рдХा рдпोрдЧ, рдмाрд╣्рдп рдХोрдгों рдХे рдпोрдЧ рдХा рджुрдЧुрдиा рд╣ै। рддрдж्рдиुрд╕ाрд░, рдЙрд╕ рдмрд╣ुрднुрдЬ рдоें рднुрдЬाрдУं рдХी рд╕ंрдЦ्рдпा рдХिрддрдиी рд╣ै?
A) 6 B) 5 C) 4 D) 8
Q8. A solid metallic cylinder of base radius 3 cm. and height 5 cm. is melted to form cones, each of height 1 cm. and base radius 1 mm. The number of cones is -
3 рд╕ेрдоी. рдд्рд░िрдЬ्рдпा рдХे рдЖрдзाрд░ рдФрд░ 5 рд╕ेрдоी. рдКँрдЪाрдИ рд╡ाрд▓े рдПрдХ рдаोрд╕ рдзाрддु рдХे рдмेрд▓рди рдХो рдкिрдШрд▓ाрдХрд░,1 рд╕ेрдоी. рдКँрдЪाрдИ рдФрд░ 1 рдоिрдоी. рдд्рд░िрдЬ्рдпा рдХे рдЖрдзाрд░ рд╡ाрд▓े рд╢ंрдХु рдмрдиाрдП рдЧрдП рд╣ै। рддрджрдиुрд╕ाрд░, рдЙрди рд╢ंрдХुрдУं рдХी рд╕ंрдЦ्рдпा рдХिрддрдиी рд╣ै?
A) 24400 B) 11600 C) 12540 D) 13500
Q9. Costs of two articles were in the ratio of 16: 23. The cost of first articles increases by 10% and that of second by Rs.477. Now the costs of two articles are in a ratio of 11: 20. The price of the second article (in Rs.) in the beginning was-
рджो рд╡рд╕्рддुрдУं рдХे рдХ्рд░рдп рдоूрд▓्рдп рдоें рдЕрдиुрдкाрдд 16: 23 рд╣ै । рдкрд╣рд▓ी рд╡рд╕्рддु рдХे рдоूрд▓्рдп рдоें 10% рдХी рд╡ृрдж्рдзि рдХी рдЬाрддी рд╣ै рдФрд░ рджूрд╕рд░ी рд╡рд╕्рддु рдХे рдоूрд▓्рдп рдоें рд░ु.477 рдХी рд╡ृрдж्рдзि рдХी рдЬाрддी рд╣ै । рдЕрдм рджोрдиों рд╡рд╕्рддुрдУं рдХे рдХ्рд░рдп рдоूрд▓्рдпों рдоें рдЕрдиुрдкाрдд 11: 20 рд╣ै । рдк्рд░ाрд░рдо्рднिрдХ рдЕрд╡рд╕्рдеा рдоें рджूрд╕рд░ी рд╡рд╕्рддु рдХा рдоूрд▓्рдп (рд░ु. рдоें) рдеा-
A) 1556 B) 1225 C) 1219 D) 2142
Q10. Two trains start from stations A and B and travel towards each other at speed of 50 km/hour and 60 km/hour respectively. At the time of their meeting, the second train has travelled 120 km more than the first. The distance between A and B is
рджो рдЯ्рд░ेрдиें рд╕्рдЯेрд╢рди A рдФрд░ B рд╕े рдПрдХ рджूрд╕рд░े рдХी рдУрд░ рдХ्рд░рдорд╢ः 50 рдХिрдоी./рдШंрдЯा рдФрд░ 60 рдХिрдоी./рдШंрдЯा рдХी рдЪाрд▓ рд╕े рдЪрд▓рдиा рд╢ुрд░ू рдХрд░рддी рд╣ैं । рдЙрдирдХे рдоिрд▓рдиे рдХे рд╕рдордп, рджूрд╕рд░ी рдЯ्рд░ेрди, рдкрд╣рд▓ी рдЯ्рд░ेрди рдХी рдЕрдкेрдХ्рд╖ा 120 рдХिрдоी. рдЕрдзिрдХ рдпाрдд्рд░ा рддрдп рдХрд░ рд▓ेрддी рд╣ै । A рдФрд░ B рдХे рдмीрдЪ рдХी рджूрд░ी рд╣ै
A) 1840 B) 1950 C) 1250 D) 1320
ANSWERS :
Q1. (B)
Let LCM be L and HCF be H, then/рдоाрдиा рд▓.рд╕.рдк. L рдФрд░ рдо.рд╕.рдк. H рд╣ै. рддो
L = 4H
and/рдФрд░ H + 4H = 125
5H = 125
H= 25
L = 4 × 25 = 100
First Number/рдкрд╣рд▓ी рд╕ंрдЦ्рдпा × Second Number/рджूрд╕рд░ी рд╕ंрдЦ्рдпा = L × H
100 × Second Number/рджूрд╕рд░ी рд╕ंрдЦ्рдпा = 25 × 100
Second Number/рджूрд╕рд░ी рд╕ंрдЦ्рдпा = 25
Q2. (D)
∠PQR = 900
∠OQR = 450 [∠PQR = 2∠OQR]
∠ORQ = 600 [ ╬ФQTR is an equilateral triangle/╬ФQTR рдПрдХ рд╕рдордмाрд╣ु рдд्рд░िрднुрдЬ рд╣ै]
∠QOR = 1800 - 600 - 450 = 750
Q3. (C)
Let the length of the train be x m./рдоाрдиा рдЯ्рд░ेрди рдХी рд▓рдо्рдмाрдИ x рдоी. рд╣ै ।
According to the question/рдк्рд░рд╢्рдиाрдиुрд╕ाрд░,
Q4. (C)
Let the required time be n years./рдоाрдиा рдЕрднीрд╖्рдЯ рд╕рдордп n рд╡рд░्рд╖ рд╣ै ।
Q5. (A)
Let/рдоाрдиा BC = x, CD = 50 - x
AC2 = 302 - x2 ...(I)
AC2 = 402 - (50 - x)2 ...(II)
From (I) and (II), we get/рд╕рдоीрдХрд░рдг (I) рдФрд░ (II) рд╕े, рд╣рдо рдк्рд░ाрдк्рдд рдХрд░рддे рд╣ैं
900 - x2 = 1600 - 2500 + 100x - x2
100x = 1800
x = 18
AC =
AE = 2 × 24 = 48 cm./рд╕ेрдоी.
Q6. (C)
Let the sum be Rs.P/рдоाрдиा рд░ाрд╢ि рд░ु.x рд╣ै ।
When compounded yearly, amount/рдЬрдм рдм्рдпाрдЬ рд╡ाрд░्рд╖िрдХ рд░ूрдк рд╕े рдк्рд░ाрдк्рдд рд╣ोрддा рд╣ै, рдоिрд╢्рд░рдзрди =
When compounded half-yearly, amount/рдЬрдм рдм्рдпाрдЬ рдЕрд░्рдж्рдзрд╡ाрд░्рд╖िрдХ рд░ूрдк рд╕े рдк्рд░ाрдк्рдд рд╣ोрддा рд╣ै, рдоिрд╢्рд░рдзрди =
So/рдЕрддः,
Q7. (A)
Let the number of sides be n/рдоाрдиा рднुрдЬाрдУं рдХी рд╕ंрдЦ्рдпा n рд╣ै।
(2n – 4)× 900 = 3600 × 2
n = 6
Q8. (D)
Q9. (C)
Let the cost price of the first article/рдоाрдиा рдкрд╣рд▓ी рд╡рд╕्рддु рдХा рдХ्рд░рдп рдоूрд▓्рдп = Rs./рд░ु.16x
and cost price of the second article/рдФрд░ рджूрд╕рд░ी рд╡рд╕्рддु рдХा рдХ्рд░рдп рдоूрд▓्рдп = Rs./рд░ु.23x
According to the question/рдк्рд░рд╢्рдиाрдиुрд╕ाрд░,
Cost price of the second article/рджूрд╕рд░ी рд╡рд╕्рддु рдХा рдХ्рд░рдп рдоूрд▓्рдп = Rs./рд░ु. (53 × 23) = Rs./рд░ु.1219
Q10. (D)
Let both trains meet after t hours/рдоाрдиा рджोрдиों рдЯ्рд░ेрдиें рдПрдХ рджूрд╕рд░े рд╕े t рдШंрдЯे рдмाрдж рдоिрд▓рддी рд╣ैं ।
Distance/рджूрд░ी = speed/рдЪाрд▓ × time/рд╕рдордп
60t - 50t = 120
10t = 120
t = 12 hours/рдШंрдЯे
Required distance/рдЕрднीрд╖्рдЯ рджूрд░ी = 60t + 50t = 110t = 110 × 12 = 1320 km./рдХिрдоी.