Quantitative Aptitude quiz is basically to test your mathematical calculation and approach. It is to find out how fast you can solve a given question with the right methodology of solving the problem. If you know the formulas and short tricks of some important topic in Maths, you will definitely score good marks. So, it is important to know the basic concept of all the topic so you can apply the short tricks and solve the question with a new concept in lesser time while giving the quiz. Quantitative Aptitude Quiz helps to evaluate your preparation for banking exam so you can improve your preparation level. Mahendra Guru provides you Quantitative Aptitude Quiz for Bank examination based on the latest pattern. So that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exam like IBPS PO/ Clerk/SO/RRB, RBI, SBI, Insurance, SSC-MTS, CGL, CHSL, State Level and other Competitive exams.
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Q-(1-3) What value will come in place of question mark (?) in the following questions?
निम्नलिखित प्रश्नों में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या मान आयेगा?
Q-1 
(1) 15
(2) 27
(3) 18
(4) 24
(5) None of these/इनमें से कोई नहीं
Q-2 83 × 642 ÷ 5122 = (8)?
(1) -2
(2) 2
(3) -1
(4) 1
(5) None of these/इनमें से कोई नहीं
Q-3 38% of 5680 - 32% of 1850 = 540 + ?
(1) 993.25
(2) 1122.4
(3) 1026.4
(4) 1241.14
(5) None of these/इनमें से कोई नहीं
Q-(4-6) In each of the following questions, two equations (I) and (II) are given. You have to solve them and state the correct relationship.
निम्नलिखित प्रश्न में दो समीकरण (I) और (II) दिये गये है दोनों समीकरण हल कीजिए और सही सम्बन्ध स्थापित कीजिये –
Q-4 (I) 15x2 + 68x + 77 = 0 (II) 3y2 + 29y + 68 = 0
(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or relationship can’t be established/ x = y या सम्बन्ध स्थापित नहीं किया जा सकता है।
Q-5 (I) 10x2 + 38x + 24 = 0 (II) 18y2 + 18y + 4 = 0
(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or relationship can’t be established/ x = y या सम्बन्ध स्थापित नहीं किया जा सकता है।
Q-6 (I) 13x2 = 32x – 12 (II) 12y2 – 22y = – 8
(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or relationship can’t be established/ x = y या सम्बन्ध स्थापित नहीं किया जा सकता है।
Q-7 A shopkeeper sells sugar at the profit of 20% and uses a weight which shows 10% less than the original weight. Find his overall profit percentage?
एक दुकानदार चीनी 20% के लाभ पर बेचता है और भार के लिए ऐसे बट्टे का प्रयोग करता है जो वास्तविक भार से 10% कम तौल दर्शाता है|,उसका कुल लाभ प्रतिशत ज्ञात कीजिये ।
(1) 10%
(2) 8%
(3) 12%
(4) 12.5%
(5) None of these/इनमें से कोई नहीं
Q-8 In how many different ways can the letters of the word 'PRACTICE' be arranged?
शब्द 'PRACTICE' के अक्षरों को कितने विभिन्न प्रकार से व्यवस्थित किया जा सकता है?
(1) 14400
(2) 40320
(3) 10080
(4) 20160
(5) None of these/इनमें से कोई नहीं
Q-9 What total amount would Akash get at the end of three years if he invests an amount of Rs.18500 in a scheme which offers compound interest @ 5.5 p.c.p.a for 3 years? (up to two places of decimal)
5.5 प्र.श.प्र.व. की चक्रवृद्धि ब्याज देने वाली योजना में 3 वर्ष के लिए 18500/- का निवेश करने पर 3 वर्ष के अन्त में आकाश को कितनी राशि मिलेगी? (दशमलव के दो अंको तक)
(1) 24815.5
(2) 29420.25
(3) 19060.6
(4) 21723.46
(5) None of these/इनमें से कोई नहीं
Q-10 If 6 men and 8 women can do a piece of work in 10 days and 26 men and 48 women can do the same in 2 days, the time taken by 15 men and 20 women to do the same type of work will be?
यदि 6 पुरूष 8 महिलाएं किसी कार्य को 10 दिनों में करती है। 26 आदमी और 48 औरतें उसी कार्य को 2 दिनों में करती है। तो उसी काम को करने में 15 आदमी और 20 औरतें को कितना समय लगेगा?
(1) 6
(2) 9
(3) 4
(4) 3
(5) None of these/इनमें से कोई नहीं
ANSWER KEY:-
Q1. (2)
Q2. (1) 83 × (8)4 ÷ (8)6 = (8)?
(8)7 – 6 = (8)?
? = 1
Q3. (3) 2158.4 – 592 – 540 = ?
? = 1026.4
Q4. (1) (I) 15x2 + 68x + 77 = 0
15x2 + 35x + 33x + 77 = 0
5x (3x + 7) + 11(3x + 7) = 0
(3x + 7) (5x + 11) = 0
x = – 7/3, x = – 11/5
(II) 3y2 + 29y + 68 = 0
3y2 + 17y + 12y + 68 = 0
y (3y + 17) + 4 (3y + 17) = 0
(3y + 17)(y + 4) = 0
y = – 17/3, y = – 4
x > y
Q5. (3) (I) 10x2 + 38x + 24 = 0
10x2 + 30x + 8x + 24 = 0
10x (x + 3) + 8(x + 3) = 0
(x + 3) (10x + 8) = 0
x = – 3, x = – 8/10
(II) 18y2 + 18y + 4 = 0
18y2 + 12y + 6y + 4 = 0
6y(3y + 2) + 2(3y + 2) = 0
(3y + 2)(6y + 2) = 0
y = – 2/3 y = – 1/3
x < y
Q6. (5) (I) 13x2 – 32x + 12 = 0
13x2 – 26x – 6x + 12 = 0
13x (x – 2) – 6(x – 2) = 0
(x – 2)(13x – 6) = 0
x = 2, x = 6/13
(II) 12y2 – 22y + 8 = 0
12y2 – 16y – 6y + 8 = 0
4y(3y – 4) – 2(3y – 4) = 0
(3y – 4)(4y – 2) = 0
y = 4/3, y = 1/2
Relationship can’t be established/ सम्बन्ध स्थापित नहीं किया जा सकता है।
Q7. (2) Let CP of 1 kg = 100
SP of 900 grams = 108
Profit percent = 8%
माना 1 किलोग्राम का क्रय मूल्य =100
900 ग्राम का विक्रय मूल्य =108
लाभ प्रतिशत=8%
Q8. (4) Total number of ways/कुल तरीके = 
Q9. Sol-(4)
Q10. (3) (6M + 8W) × 10 = (26M + 48W) × 2
60M + 80W = 52M + 96W
1M = 2W
15M + 20W = 15M + 10M = 25M
10M × 10 = 25M × ?
10M × 10 = 25M × ?
