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Q1. Find the least number which when divided by 2 , 3, 4 , 5 ,6 leaves remainder in 3 each case but when divided by 7 leaves 2 remainder.
सबसे छोटी संख्या ज्ञात कीजिये जिसको 2 , 3, 4 , 5 ,6 से भाग देने पर 3 शेषफल बचता है लेकिन 7 से भाग देने पर 2 शेषफल बचता है।
(A) 60 (B) 293 (C) 300 (D) 303
Q2. How many numbers less than 1000 are multiples of both of 10 and 13 ?
कितने संख्या 1000 की तुलना में कम से कम 10 और 13 दोनों के गुणनफल हैं?
(A) 5 (B) 7 (C) 8 (D) 9
Q3. Mohan gets 4 marks for each correct sum and losses 1 marks for each wrong sum. He attempted 30 sum and obtains 50 marks. The number of sums solved correctly is?
मोहन को प्रत्येक सही प्रश्न के लिए 4 अंक और प्रत्येक गलत प्रश्न के लिए 1 अंक काट लिए जाता है। वह 30 प्रश्न करता है और 50 अंक प्राप्त करता है। सही प्रश्नो की संख्या क्या है?
(A) 20 (B) 15 (C) 16 (D) 18
Q4. If
operation such that for positive integers a and b , a
= - a + b - (-2), then the value of 4
is :
यदि ∆ कोई संक्रिया है जैसे कि धनात्मक पूर्णांकों के लिए a और b, a ∆ b =-a + b-(-2), तो 4 ∆ 3 का मान है:
(A) 1 (B) -1 (C) +3 (D) -3
Q5. If
+
+
(A) 1 (B) 3 (C)
(D)
Q6. If
-1/2 then the value of
(A) 2 (B) -
(C)
(D)
Q7. If a sphere of radius r is divided into four identical parts., then the total surface area of the four parts is-
यदि एक गोले को चार बराबर भाग में बांटा जाता है तो चारो गोलों का कुल क्षेत्रफल ज्ञात कीजिये-
(A)
(B)
Q8.
then the value of
is
(A) 1 (B) 41 (C) 441 (D) 400
Q9. If
(A) 4 (B) 5 (C) 7 (D) 8
Q10. If
+
(A) 1 (B) -1 (C) 2 (D) 0
Answer Key-
Q1-(D) Out of the given option only 303 satisfy the condition.
दिए गए विकल्प से केवल 303 ही दी गयी स्थिति को संतुष्ट करेगा
Q2-(B) 10 and 13 are co-prime numbers. Product of 10 and 13 = 10
1000![](https://blogger.googleusercontent.com/img/proxy/AVvXsEhrosmREf47mCGT__nDICjJTd0gQEtknsKOZtG74AnDg0tdJGPEquTDsePn95SFMqoFnKG7ikZTMNASR6qdd1a3wPPrcdMyvGYrBOoVjpTCS-gxEn8lZb7C_H6nB-V2QrwPeZ4XjkQruEXRuzjB9NTUv6XFOkDusrTgzgWdidzcZp4_hA93D3slTj3CVicTGYOzdnQSukeHAKPJGRZLMQk=)
So answer is 7.
10 और 13 सह-प्रमुख संख्या है। 10 और 13 के उत्पाद = 10 × 13 = 130
1,000 ÷ 13 = 7 (भागफल) +90 (शेष) 1,000 ÷ 13 = 7 (भागफल) +90 (शेष)
अतः सही उत्तर 7 है।
Q3-(C) Let he attempted x sums correctly.
Then his total marks = ![](https://blogger.googleusercontent.com/img/proxy/AVvXsEjwjDoJput8uOPehtJUwWBHFQQiUzofthpCL2wge5ZPU-KQ-HUnzuYJubNgO8omlAKWlPXnENTQ57qsYnfTJd1C8_JW2sV1K7rr5JXGQyix4LmvOINRGiuU3wfumcrl6TzP2I5zzanaUD66Z089pC5qjli0Qnzv3tcCa3c3aBT3tjsgI2MRCxhv9VvXM9m53GIZF3glDnzLQ4nJRbIxYYc=)
माना कि उसने x प्रश्न सही किये
तो उसके कुल अंक =
Q4-(A) a
= - a + b - (-2),
4
= -4 +3 – (-2)
-1 + 2 = 1.
Q5-(D) =
Q6-(A)
Q7-(C) Required total surface area =
+
=
अभीष्ट छेत्रफल =
+
=
Q8-(A) Expression =
समीकरण =
Q9-(C)
Dividing numerator and denominator by x,
Q10-(A)
=
+![](https://blogger.googleusercontent.com/img/proxy/AVvXsEjGIaflGy3-HS7vN0kWY3WK0CFS026fcTmuCImJ1moQiEc6hnnWUbCFBj1CTEt08cbSPOdftE7iPOHeiy8NHSlTyiEH9FabJH4cdevqhU82CeQdxidD_q0RifH-I_wJDz8OBPpQ7xozhtCtJiNDB3WQRDq8_Ryl42z6-JWtUGeJ-xfEWWdRdNvvED-HDypK4Kt-sIJvUNzZ4Bd0qS6sDK0=)
=
= ![](https://blogger.googleusercontent.com/img/proxy/AVvXsEjBspZYtzIczxCve0ITaUE39depQxpi5cp8Gm_Fn9x-eGNOJZQO6j1GM3nSvzCdo-iUKIw8xbxHJouklW8QNfx_iGunzLd_s9rgD38pN3jaANvgbf3zPkNVzmBORqN7uW6q7RGJsc7P-iaWBflJoz0A0zGMr2ZChKSF4yRTyD3S1l8B_rqvT8MJ0jl45LphyfX3v8wv4uBl_6zNjbGLcJw=)
= 1