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Quantitative Aptitude Quiz For IBPS PO/Clerk | 26-09-19

Mahendra Guru
Quantitative Aptitude Quiz For IBPS  PO/Clerk | 26-09-19
Dear Readers,

As IBPS has released the much-awaited vacancies for the post of Junior Assistants (Clerk) & PO, we have launched subject-wise quizzes for the exam. It will include quizzes of all the subjects- Quantitative Aptitude, English, Reasoning and Computer. All these quizzes will be strictly based on the latest pattern of IBPS PO/Clerk exam and will be beneficial for your preparations. So, keep following the quizzes which will provide you a set of 10 questions daily.
Here, we are providing you important questions of Quantitative Aptitude for IBPS PO/Clerk 2019 exam.

Q-(1-5) What value will come in place of question mark (?) in the questions given below ?

निम्नलिखित प्रश्नों में प्रश्नवाचक चिन्ह ( ?) के स्थान पर क्या मान आयेगा ?

(1)
188×18×8-8088 = ?

(1) 18984
(2) 19022 
(3) 18816
(4) 18626 
(5) 18920

(2) 64% of 842 – ?% of 426 =334.4

(1) 34
(2) 38 
(3) 42
(4) 46 
(5) 48

(3) 9984 ÷http://onlinespeedtest.mahendras.org/Images/138751030576962.png = 384

(1) 636
(2) 646 
(3) 656
(4) 666 
(5) 676

(4) (16)3- (16)2 = ?

(1) 3840
(2) 3620 
(3) 3710
(4) 3550 
(5) 3320

(5) 26831 + 8348 - 2061 = ? × 58

(1) 569
(2) 573 
(3) 575
(4) 571 
(5) 582

Q-(6-10) In each of the following questions, two equations (I) and (II) are given. You have to solve them and Give answer-

निम्नलिखित प्रश्नों में दो समीकरण (I) और (II) दिये गये है दोनों समीकरण हल कीजिए और - उत्तर दीजिए 


(6) (I)   10x2 -33x+27 = 0             
     (II)  18y2 - 17y +4 = 0

(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or relationship cannot be established

(7) (I)   2x2 + 5x - 12 = 0                
      (II)   2y2 + 5y - 7 = 0

(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or relationship cannot be established

(8) (I)   2x2 + 9x + 10 = 0       
     (II)   2y2 + 17y + 30 = 0

(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or relationship cannot be established

(9) (I)    17x - 57 = 300 -4x        
      (II)   y = http://onlinespeedtest.mahendras.org/Images/13620077209555.png

(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or relationship cannot be established

(10) (I)   6x2 - 19x + 15  = 0        
        (II)   4y2 -16y + 15 = 0

(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or relationship cannot be established

Answer Key-
  1. Sol-(1)
? = 27072 – 8088 = 18984

       2. Sol-(5)

http://onlinespeedtest.mahendras.org/Images/138750996210068.jpg

       3. Sol-(5)

http://onlinespeedtest.mahendras.org/Images/138751037841929.jpg

      4. Sol-(1)

? = 4096 – 256 = 3840

       5. Sol-(4)

http://onlinespeedtest.mahendras.org/Images/138750943528868.jpg

       6. Sol-(1)

(I)   10x2-15x-18x+27 = 0
 5x(2x - 3) -9(2x-3) = 0
x = http://onlinespeedtest.mahendras.org/Images/136200507116605.png, http://onlinespeedtest.mahendras.org/Images/13620051019449.png
(II)    18y2 - 9y -8y+4 = 0
9y(2y-1) -4(2y-1) = 0
y = http://onlinespeedtest.mahendras.org/Images/136200512988455.png, http://onlinespeedtest.mahendras.org/Images/136200514612418.png
x > y

      7. Sol-(5)

(I)  2x2 +8x -3x-12 = 0
      2x(x+4) -3(x+4) = 0
      x = http://onlinespeedtest.mahendras.org/Images/136200593102396.png ,-4
(II)  2y2 +7y-2y-7 =0
       y(2y+7)-1(2y+7) = 0
       y = 1, http://onlinespeedtest.mahendras.org/Images/136200596414282.png
        So relationship can not be set up.

       8. Sol-(2)

(I)   2x2 + 4x +5x+ 10 = 0
       2x(x+2) +5 (x+2) = 0
       x = http://onlinespeedtest.mahendras.org/Images/136200730170477.png,-2
(II)  2y2 + 12y + 5y +30 = 0
       2y(y+6) +5(y+6) = 0
       y = -6, http://onlinespeedtest.mahendras.org/Images/136200734151604.png
    http://onlinespeedtest.mahendras.org/Images/136200735474486.png   x > y

       9. Sol-(5)

(I)   17x + 4x = 357
       21x = 357
        x = 17
 (II)  y = 17
         http://onlinespeedtest.mahendras.org/Images/136200801885363.pngx = y

       10. Sol-(5)

(I)    6x2 - 10x -9x +15 = 0
        2x(3x-5) -3(3x-5) = 0
        x = http://onlinespeedtest.mahendras.org/Images/136200853527693.png
 (II)    4y2 - 10y -6y +15 = 0
          2y(2y-5) -3(2y-5) = 0
          y = http://onlinespeedtest.mahendras.org/Images/136200858493182.png       
So, relation can't be established.

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