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Quantitative Aptitude Quiz For IBPS PO/Clerk | 04-10-19

Mahendra Guru
Quantitative Aptitude Quiz For IBPS  PO/Clerk | 04-10-19
Dear Readers,

As IBPS has released the much-awaited vacancies for the post of Junior Assistants (Clerk) & PO, we have launched subject-wise quizzes for the exam. It will include quizzes of all the subjects- Quantitative Aptitude, English, Reasoning and Computer. All these quizzes will be strictly based on the latest pattern of IBPS PO/Clerk exam and will be beneficial for your preparations. So, keep following the quizzes which will provide you a set of 10 questions daily.
Here, we are providing you important questions of Quantitative Aptitude for IBPS PO/Clerk 2019 exam.

Q(1-5) : What will come in place of question mark (?) in the following series?

निम्न संख्या श्रृंखलाओं में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या आयेगा ?

(1) 36      222      ?       4464       13395       26792


(1) 3245
(2) 3345
(3) 2230
(4) 1110
(5) 1115

(2) 0        7       26      63      124       ?

(1) 212
(2) 213
(3) 214
(4) 215
(5) 185

(3) 636      997       ?        1511       1680        1801

(1) 1376
(2) 1286
(3) 1186
(4) 1486
(5) 1411

(4) 765       804       882       ?       1155        1350

(1) 998
(2) 1001
(3) 999
(4) 1002
(5) 966

(5) 32.50        146.25         585       ?         6142.5        15356.25

(1) 2025.5
(2) 2027.25
(3) 2037.5
(4) 2045.25
(5) 2047.5

(6) A train goes from one place to another place without stoppages at the average speed of 90 km./hr while other train goes the same distance with stoppages at the average speed of 75 km./hr. Find how many minutes that train stops per hour?

एक ट्रेन बिना रुके 90 किमी./घंटा की औसत चाल से एक स्थान से दूसरे स्थान तक जाती है | जबकि दूसरी ट्रेन रुक - रुक कर वही यात्रा 75 किमी./घंटा की औसत चाल से पूरी करती है |बताइये वह प्रति घंटा कितने मिनट रूकती है ?


(1) 8 minutes
(2) 10 minutes
(3) 12 minutes
(4) 15 minutes
(5) 6 minutes

(7) A boat takes 4 hours to go from one place to another and to to return from that place to the starting point. If speed of the current is 2 km./hr and speed of the boat in still water is 4 km./hr. Find the distance between the two places.

एक नाव नदी में एक स्थान से दूसरे स्थान तक जाने और पुनः वापस आने में 4 घंटे का समय लेती है | यदि नदी का वेग 2 किमी./घंटा तथा स्थिर जल में नाव की चाल 4 किमी./घंटा है |तो दोनों स्थानों के बीच की दूरी ज्ञात कीजिये | 


(1) 6 km.
(2) 8 km.
(3) 10 km.
(4) 12 km.
(5) 15 km.

(8) If the length of the rectangle be decreased by 20% and breadth of the rectangle be decreased by 15%. Then what will be the change in area of the rectangle?


यदि आयत की लम्बाई को 20% घटा दिया जाय और आयत की चौड़ाई को 15% घटाया जाय | तो आयत के क्षेत्रफल में कितना परिवर्तन आएगा ?


(1) 23%
(2) 25%
(3) 28%
(4) 30%
(5) 32%

(9) Rs.24000 per month. If the expenditure of S is thrice that of P, then the average expenditure of Q and R is 

P, Q और R का औसत मासिक व्यय 18000 रु. प्रति माह है और Q, R और S का औसत मासिक व्यय 24000 रु. प्रति माह है | यदि S का व्यय P के व्यय का तीन गुना है, तो Q और R का औसत व्यय है 


(1) Rs.20500
(2) Rs.24500
(3) Rs.22500
(4) Rs.26000
(5) None of these
(10) The simple interest accrued on a certain sum is Rs.40761 in 9 years at the rate of 7 p.c.p.a. What would be the compound interest accrued on that sum at the rate of 5 p.c.p.a. in 2 years?

एक निश्चित धनराशि पर 9 वर्ष में 7 प्रतिशत वार्षिक ब्याज की दर से साधारण ब्याज 40761 रु. है | उसी धनराशि पर 2 वर्ष में 5% वार्षिक ब्याज की दर से चक्रवृद्धि ब्याज क्या होगा ?


(1) Rs.7631.75
(2) Rs.6613.75
(3) Rs.6631.75
(4) Rs.6630.75
(5) Rs.6836.75
Answer Key-

1. Sol-(5)

×6+6, ×5+5, ×4+4, ×3+3, ×2+2

2. Sol-(4)

13-1, 23-1, 33-1, 43-1, 53-1, 63-1

3. Sol-(2)

+192, + 172, +152, + 132, 112

4. Sol-(3)

+39, +78, +117, +156, +195

5. Sol-(5)

×4.5, ×4, ×3.5, ×3, ×2.5

6. Sol-(2)

  1. Required time =
                      = (15/90) hours
                      = (1/6) hours
                      = (1/6) × 60 minutes
                      = 10 minutes

7. Sol-(1)

Speed of the downstream = 4 + 2 = 6 km./hr
Speed of the upstream = 4 - 2 = 2 km./hr
Let the distance between two places be x km.

Distance between two places = 6 km

8. Sol-(5)

% change = -20 - 15 + [{(-20)(-15)}/100]
                = -35 + 3
                = -32%

9. Sol-(3)

10. Sol-(3)

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