In SSC exam, quantitative Aptitude section is more scoring and easy, if you know the shorts tricks and formulas of all the topics. So, it is important to know the basic concepts of all the topics so you can apply the short tricks and solve the question with the new concepts in lesser time while giving the quiz. It will help you to score more marks from this section in less time period. Quantitative Aptitude section basically measures your mathematical and calculation approach of solving the question. SSC Quiz of quantitative Aptitude section helps you to analyse your preparation level for the upcoming SSC examination. Mahendra Guru provides you Quantitative Aptitude Quiz for SSC examination based on the latest pattern so that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exams like Insurance, SSC-MTS, SSC CPO, CGL, CHSL, State Level, and other Competitive exams.
(A) 62
(B) 32
(C) 56.5
(D) 57
Q. 1. 67, 34, 57, 32, 12, 92, 51, 62, 62, 57, 93 рдФрд░ 5 рдХी рдоाрдз्рдпिрдХा рдЬ्рдЮाрдд рдХीрдЬिрдпे?
(A) 62
(B) 32
(C) 56.5
(D) 57
Q. 2. If 20 men work 7 hours in a day and finish a work in 10 days, then in how many days will 15 men finish the same work after working 8 hours in a day?
(A) days
(B) days
(C) days
(D) days
Q. 2. рдпрджि 20 рдЖрджрдоी рдПрдХ рджिрди рдоें 7 рдШрдг्рдЯे рдХाрдо рдХрд░рдХे рдПрдХ рдХाрдо рдХो 10 рджिрди рдоे рд╕рдоाрдк्рдд рдХрд░рддे рд╣ैं, рддो 15 рдЖрджрдоी рдПрдХ рджिрди рдоें 8 рдШрдг्рдЯे рдХाрдо рдХрд░рдХे рдЙрд╕ी рдХाрдо рдХो рдХिрддрдиे рджिрди рдоे рд╕рдоाрдк्рдд рдХрд░ेंрдЧे?
(A) рджिрди
(B) рджिрди
(C) рджिрди
(D) рджिрди
Q. 3. A man says to his son, ''Seven years ago I was seven times as old as you were and three years hence I will be three times as old as you will be.'' Find their ages.
(A) 42, 12
(B) 40, 14
(C) 20, 42
(D) 52, 12
Q. 3. рдПрдХ рдЖрджрдоी рдЕрдкрдиे рдмेрдЯे рд╕े рдХрд╣рддा рд╣ै, ''рд╕ाрдд рд╡рд░्рд╖ рдкрд╣рд▓े рдоैं рддुрдо्рд╣ाрд░ी рдЖрдпु рдХा рд╕ाрдд рдЧुрдиा рдеा рдФрд░ рддीрди рд╡рд░्рд╖ рдмाрдж рдоैं рддुрдо्рд╣ाрд░ी рдЖрдпु рдХा рддीрди рдЧुрдиा рд╣ोрдКंрдЧा ।’’ рдЙрдирдХी рдЙрдо्рд░ рдЬ्рдЮाрдд рдХीрдЬिрдпे ।
(A) 42, 12
(B) 40, 14
(C) 20, 42
(D) 52, 12
Q. 4. The average marks scored by a student in 5 subjects is 75. The average marks scored by him in the first two subjects is 65. The average marks scored by him in the last two subjects is 85. How many marks did the student score in the third subject?
(A) 80 marks
(B) 70 marks
(C) 65 marks
(D) 75 marks
Q. 4. 5 рд╡िрд╖рдпों рдоें рдПрдХ рдЫाрдд्рд░ рдж्рд╡ाрд░ा рдк्рд░ाрдк्рдд рдФрд╕рдд рдЕंрдХ 75 рд╣ैं । рдЙрд╕рдХे рдж्рд╡ाрд░ा рдкрд╣рд▓े рджो рд╡िрд╖рдпों рдоें рдк्рд░ाрдк्рдд рдФрд╕рдд рдЕंрдХ 65 рд╣ैं। рдЕंрддिрдо рджो рд╡िрд╖рдпों рдоें рдЙрд╕рдХे рдж्рд╡ाрд░ा рдк्рд░ाрдк्рдд рдФрд╕рдд рдЕंрдХ 85 рд╣ैं । рдЫाрдд्рд░ рдиे рддीрд╕рд░े рд╡िрд╖рдп рдоें рдХिрддрдиे рдЕंрдХ рдк्рд░ाрдк्рдд рдХिрдП рд╣ैं?
(A) 80 рдЕंрдХ
(B) 70 рдЕंрдХ
(C) 65 рдЕंрдХ
(D) 75 рдЕंрдХ
Q. 5. The numerical value of the area of an equilateral triangle is equal to twice the numerical value of its perimeter. What is the area of the said triangle?
(A) sq. unit
(B) sq. unit
(C) 48 sq. unit
(D) sq. unit
Q. 5. рдПрдХ рд╕рдордмाрд╣ु рдд्рд░िрднुрдЬ рдХे рдХ्рд╖ेрдд्рд░рдлрд▓ рдХा рд╕ंрдЦ्рдпाрдд्рдордХ рдоाрди рдЗрд╕рдХी рдкрд░िрдзि рдХे рд╕ंрдЦ्рдпाрдд्рдордХ рдоाрди рдХे рджोрдЧुрдиे рдХे рдмрд░ाрдмрд░ рд╣ै। рдЙрдХ्рдд рдд्рд░िрднुрдЬ рдХा рдХ्рд╖ेрдд्рд░рдлрд▓ рдХिрддрдиा рд╣ै?
(A) рд╡рд░्рдЧ рдЗрдХाрдИ
(B) рд╡рд░्рдЧ рдЗрдХाрдИ
(C) 48 рд╡рд░्рдЧ рдЗрдХाрдИ
(D) рд╡рд░्рдЧ рдЗрдХाрдИ
Q. 6. What should be added to the expression x (x + a) (x + 2a) (x + 3a) so that the sum may be a perfect square?
(A) 9a2
(B) 4a2
(C) a4
(D) a2
Q. 6. рд╡्рдпंрдЬрдХ x (x + a) (x + 2a) (x + 3a) рдоें рдХ्рдпा рдЬोреЬा рдЬाрдиा рдЪाрд╣िрдП рдЬिрд╕рд╕े рдХि рдпोрдЧрдлрд▓ рдПрдХ рдкूрд░्рдг рд╡рд░्рдЧ рд╣ो рд╕рдХे ?
(A) 9a2
(B) 4a2
(C) a4
(D) a2
Q. 7. Find the value of cos (2580o). (A)
(B)
(C)
(D) 0
Q. 7. cos (2580o) рдХा рдоाрди рдЬ्рдЮाрдд рдХीрдЬिрдП । (A)
(B)
(C)
(D) 0
Q. 8. 40% of 20% + 30% of 25% + 50% of 28% is equivalent to
(A) 29.5%
(B) 28.5%
(C) 30.5%
(D) 31.5%
Q. 8. 40% рдХा 20% + 30% рдХा 25% + 50% рдХा 28% рдХे рдмрд░ाрдмрд░ рд╣ै-
(A) 29.5%
(B) 28.5%
(C) 30.5%
(D) 31.5%
Q. 9. If a + b + c = 13 and ab + bc + ca = 25 then (a3 + b3 + c3 – 3abc) =?
(A) 1222
(B) 1333
(C) 1369
(D) 1444
Q. 9. рдпрджि a + b + c = 13 рдФрд░ ab + bc + ca = 25 рддो (a3 + b3 + c3 – 3abc) =?
(A) 1222
(B) 1333
(C) 1369
(D) 1444
Q. 10. A boat goes at 6 km. upstream and back again to starting point in 2 hours. If the speed of the current in 4 km. /hr., what is the speed of the boat in still water?
(A) 4 kmph
(B) 6 kmph
(C) 8 kmph
(D) 12 kmph
Q. 10. рдПрдХ рдиाрд╡ рдзाрд░ा рдХे рдк्рд░рддिрдХूрд▓ 6 рдХिрдоी. рдЬाрдХрд░ рдЙрд╕ी рдк्рд░ाрд░рдо्рднिрдХ рд╕्рдеाрди рдкрд░ 2 рдШंрдЯे рдоें рд╡ाрдкрд╕ рдЖ рдЬाрддी рд╣ै। рдпрджि рдзाрд░ा рдХी рдЪाрд▓ 4 рдХिрдоी. /рдШं. рд╣ै рддो рд╢ाрди्рдд рдЬрд▓ рдоें рдиाрд╡ рдХी рдЪाрд▓ рдХ्рдпा рд╣ै?
(A) 4 рдХिрдоी. /рдШं.
(B) 6 рдХिрдоी. /рдШं.
(C) 8 рдХिрдоी. /рдШं.
(D) 12 рдХिрдоी. /рдШं.
Solutions:
1. Sol. (D)
рджिрдпे рдЧрдП рдк्рд░ेрдХ्рд╖рдгों рдХो рдЖрд░ोрд╣ी рдХ्рд░рдо рдоें рд╡्рдпрд╡рд╕्рдеिрдд рдХрд░рдиे рдкрд░
5, 12, 32, 34, 51, 57, 57, 62, 62, 67, 92, 97
n = 12
рдЕрддः, рдоाрдз्рдпिрдХा = ½ [6рд╡ाँ рдкрдж + 7рд╡ाँ рдкрдж] = 572.
2.Sol. (B)
Men 15: 20
:: 10: x
Hours 8: 7
According to the question,
15 × 8 × x = 20 × 7 × 10
x = days
3. Sol. (A)
M – 7 = 7 (S – 7)
M – 7S = – 42 … (i)
M + 3 = 3 (S + 3)
M – 3S = 6 … (ii)
From (i) and (ii), we get
M = 42, S = 12
4. Sol. (D)
рддीрд╕рд░े рд╡िрд╖рдп рдоें рдЕंрдХ = 5 × 75 – 2 × 65 – 2 × 85
= 375 – 130 – 170
= 75
5. Sol. (B)
According to the question,
a = 8
Area of the equilateral triangle = = sq. unit
6. Sol. (C)
x (x + a) (x + 2a) (x + 3a) + a4 = (x2 + a2 + 3ax)2
Hence, Term to be added = a4
7. Sol. (B)
cos 2580o = cos (2520o + 60o)
= cos(7 × 360o + 60o)
= cos 60o =
8. Sol. (A)
40% of 20% + 30% of 25% + 50% of 28%
= 8% + 7.5% + 14% = 29.5%
9. Sol. (A)
(a3 + b3 + c3 – 3abc) = [(a + b + c)2 – 3 (ab + bc + ca)]
(a3 + b3 + c3 – 3ab) = = 13 × [(13)2 – 3 × 25]
= 13 × 94 = 1222
10. Sol. (C)
Let speed of the boat in still water be x km. /hr.
According to the question,
12 x = 2(x2 – 16)
12 x = 2x2 – 32
2x2 – 12x – 32 = 0
x2 – 6x – 16 = 0
x2 – 8x + 2x – 16 = 0
x (x – 8) + 2(x – 8) = 0
(x – 8) (x + 2) = 0
x = 8, – 2
Speed of the boat in still water = 8 km./hr.