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SSC Quiz : Quantitative Aptitude | 01- 11 - 19

Mahendra Guru
SSC Quiz : Quantitative Aptitude | 01- 10 - 19

In SSC exam, quantitative Aptitude section is more scoring and easy, if you know the shorts tricks and formulas of all the topics. So, it is important to know the basic concepts of all the topics so you can apply the short tricks and solve the question with the new concepts in lesser time while giving the quiz. It will help you to score more marks from this section in less time period. Quantitative Aptitude section basically measures your mathematical and calculation approach of solving the question. SSC Quiz of quantitative Aptitude section helps you to analyse your preparation level for the upcoming SSC examination. Mahendra Guru provides you Quantitative Aptitude Quiz for SSC examination based on the latest pattern so that you can practice on regular basis. It will definitely help you to score good marks in the exam. It is the most important section for all the govt exams like Insurance, SSC-MTS, SSC CPO, CGL, CHSL, State Level, and other Competitive exams.
So, here we will provide you a set of 10 questions of Quantitative Aptitude, important for SSC  exam.

Q. 1. The ratio of income A to B is x: 8 and the ratio of B to C is 12: z. If the ratio of A to C is 2: 1, then what is the ratio of x: z?

(A) 4: 3

(B) 2: 3

(C) 3: 4

(D) 3: 2

Q. 1. A का B से अनुपात x: 8 है और B का C से अनुपात 12: z है। यदि A का C से अनुपात 2: 1 है,तो x: z का अनुपात क्या है?

(A) 4: 3

(B) 2: 3

(C) 3: 4

(D) 3: 2

Q. 2. The ratio between the numbers of sides of two regular polygons is 1: 2 and the ratio between their interior angles is 2: 3. The sum of the number of sides of these polygons is –

(A) 18 

(B) 15

(C) 12

(D) 21

Q. 2. दो समबहुभुज के भुजाओं की संख्याओं का अनुपात 1: 2 है एवं उनके प्रत्येक अंतःकोण के मान का अनुपात 2: 3 है, तो उन समबहुभुज की भुजाओं की संख्या का योग है-

(A) 18 

(B) 15

(C) 12

(D) 21

Q. 3. If the distance between the points (x, 0) and (– 7, 0) be 10 units, then the possible values of x are

(A) 3 and – 17

(B) – 3 and – 17

(C) 3 and 17

(D) – 3 and 17

Q. 3. यदि (x, 0) तथा (– 7, 0) बिन्दुओं के बीच की दूरी 10 एकक हो, तो x के संभावित मान क्या होंगे?

(A) 3 और – 17

(B) – 3 और – 17

(C) 3 और 17

(D) – 3 और 17

Q. 4. 4% of selling price of an article is equal to 5% of its cost price. Again 20% of the selling price is Rs.120 more than 22% of its price. The difference of cost price and selling price

(A) Rs.2500 

(B) Rs.2000

(C) Rs.1500

(D) Rs.1000

Q. 4. किसी वस्तु के विक्रय मूल्य का 4% उसके क्रय मूल्य के 5% के बराबर है । पुनः विक्रय मूल्य का 20% उसके क्रय मूल्य के 22% से 120 रु. अधिक है । क्रय मूल्य और विक्रय मूल्य का अन्तर ज्ञात कीजिये ।

(A) रु.2500 

(B) रु.2000

(C) रु.1500

(D) रु.1000

Q. 5. If the length of the parallelepiped is 3 times of its breadth and 6 times of its height and its volume is 768000 cm³, then its total surface area will be:

(A) 6400 cm² 

(B) 64000 cm²

(C) 3200 cm²

(D) 32000 cm²

Q. 5. यदि एक घनाभ का लम्बाई, इसकी चौड़ाई का 3 गुना और ऊँचाई का 6 गुना है तथा इसका आयतन 768000 घन सेमी हो, तो इसका कुल पृष्ठीय क्षेत्रफल होगा-

(A) 6400 सेमी² 

(B) 64000 सेमी²

(C) 3200 सेमी²

(D) 32000 सेमी²

Q. 6. If (a2 + b2) (m2 + n2) = (am + bn)2 then which one of the following is true ?

(A) a2n = b2m

(B)

(C)

(D)

Q. 6. यदि (a2 + b2) (m2 + n2) = (am + bn)2 तो निम्न से कौन सा सही है ?

(A) a2n = b2m

(B)

(C)

(D)


Q. 7. A man goes 12 km upstream and back again to the starting point in 4 hours. If the speed of water is 4 km/hr. Find the speed of the boat.

(A) 6.5 kmph 

(B) 7 kmph

(C) 8 kmph

(D) 5 kmph

Q. 7. एक आदमी 12 किमी.ऊर्ध्वप्रवाह जाता है और प्रारम्भिक बिंदु पर आने में 4 घंटे लेता है | यदि पानी की गति 4 किमी./घंटा है | नाव की गति ज्ञात कीजिये |

(A) 6.5 किमी. /घंटा

(B) 7 किमी. /घंटा

(C) 8 किमी. /घंटा

(D) 5 किमी. /घंटा

Q. 8. Two trains can cross a pole in 14 sec. and 16 sec. respectively. Find in how much time will they cross each other if they are coming from same direction and if the speed of the trains are in the ratio of 7 : 9?

(A) 111 sec. 

(B) 119 sec. 

(C) 131 sec. 

(D) 121 sec. 

Q. 8. दो ट्रेनें एक खम्भे को क्रमशः 14 से. और 16 से. पर करती हैं | ज्ञात कीजिये कि कितने समय में वह एक दूसरे को पार कर लेंगी यदि वे एक ही दिशा से आ रही हैं और यदि ट्रेनों की गतियों का अनुपात 7 : 9 में है ?

(A) 111 से.

(B) 119 से. 

(C) 131 से. 

(D) 121 से. 

Q. 9. 80 men can complete a work in 30 days. They start work together and after every 10 days 10 men left the work. In how much time work will be completed?

(A) 30 days 

(B) 32 days

(C) 36 days

(D) 46 days

Q. 9. 80 आदमी एक कार्य को 30 दिन में कर सकते हैं | वे काम करना शुरू करते हैं और प्रत्येक 10 दिन बाद 10 व्यक्ति काम छोड़ देते हैं | कितने समय में यह काम पूरा हो जाएगा?

(A) 30 दिन

(B) 32 दिन

(C) 36 दिन

(D) 46 दिन

Q. 10. A shopkeeper sold an article for Rs.17940 with a discount of 8% and gained 19.6%. If no discount is allowed, what will be his gain percent?

(A) 25%

(B) 26.4%

(C) 30%

(D) 28%

Q. 10. एक दुकानदार एक वस्तु को रु.17490 में 8% की छूट देकर बेचता है और 19.6% का लाभ प्राप्त करता है | यदि कोई छूट नहीं दी गयी है तो, उसका लाभ प्रतिशत क्या होगा ?

(A) 25%

(B) 26.4%

(C) 30%

(D) 28%



Answers:

1. Sol. (A)

A: B = x: 8

B: C = 12: z

A: C =

प्रश्नानुसार,


x: z = 4: 3

2. Sol. (C)

According to the question,


On solving above, we get

n = 4

Sum of the number of sides of both the polygons = 4 + 8 = 12

3. Sol. (A)

According to the question,

(x + 7)2 = 100

x2 + 49 + 14x = 100

x2 + 14x – 51 = 0

x = – 17, 3

4. Sol. (D)

4% S.P. = 5% C.P. … (i)

20% S.P. = 22% C.P. + 120 … (ii)

25% C.P. = 22% C.P. + 120

3% C.P. = 120

C.P. = 4000

S.P. = 5000

Required difference = Rs.1000

5. Sol. (B) 

Let height = x

length = 6x

breadth = 2x

According to the question,

x × 6x × 2x = 768000

x = 40

Total surface area of the parallelepiped = 2 (40 × 240 + 240 × 80 + 80 × 40)

= 64000 cm²

6. Sol. (B)

(a2 + b2) (m2 + n2) = (am + bn)2

a2m2 + b2m2 + a2n2 + b2n2 = a2m2 + b2n2 + 2abmn

b2m2 + a2n2 = 2abmn

(an – bm)2 = 0

an = bm

a/m = b/n

7. Sol. (C)


Using options,

B = 8 km.

8. Sol. (D)

Distance moved by first train in crossing a pole = 14 × 7 = 98 m.

Distance moved by second train in crossing a pole = 16 × 9 = 144 m.

Total distance in crossing each other = 98 + 144 = 242 m.

Relative speed = 9 – 7 = 2

Time = 242/2 = 121 sec.

9. Sol. (C)

Total work = 80M × 30D = 2400

80M × 10 = 800

70M × 10 = 700

60M × 10 = 600

50M × 6 = 300

Total = 2400

Number of days = 10 + 10 + 10 + 6 = 36 days

10.Sol. (C)

Discount = 8%

S.P = 17940

MP =

Now, gain = 19.6%

CP =

Gain = 19500 - 15000 = Rs./रु.4500

Gain % =

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