mahendras

| Join Mahendras Telegram Channel | Like Mahendras Facebook Page | Online Admission | Download Mahendras App

Now Subscribe for Free videos

Subscribe Now

SSC CGL & CHSL Quiz : Quantitative Aptitude | 29 -01-2020

Durgesh Mahendras
SSC CGL & CHSL Quiz : Quantitative Aptitude | 29 -01-2020




As SSC CGL notification is out and candidates have started their preparation for this exam. Mahendras also has started special quizzes for this examination. This series of the quizzes is based on the latest pattern of the SSC CGL examination. Regular practice of the questions included in the quizzes will boost up your preparations and it will be very helpful in scoring good marks in the examination.



Q.1-  what is the value of following expression?

निम्न लिखित एक्सप्रेशन का मान क्या होगा 


SSC-CGL-MATHS-29-01-2020 


(1) SSC-CGL-MATHS-29-01-2020
(2) SSC-CGL-MATHS-29-01-2020
(3) SSC-CGL-MATHS-29-01-2020
(4)SSC-CGL-MATHS-29-01-2020


Q.2:-If x be the largest 4 digit number which when divided by 3, 4, 5, 6, 7, and 8 leaves remainder 2 in each case what is the sum of digit of x?

यदि x 4 अंको की बड़े से बड़ी संख्या है जिसको 3, 4, 5, 6, 7, और  8 से विभाजित करने पर प्रत्येक बार 2 शेष बचाता है तो x के अंकों का योग क्या होगा ?

(1) 13
(2) 11
(3) 12
(4) 8


Q.3:- A field is in a shape of trapezium whose parallel sides are 300 and 400 m their unparalleled side are 130 m then what the area of trapezium?

एक खेत का का आकार समलम्ब चतुर्भुज के सामान है यदि उसकी समान्तर भुजाएं 300 और 400 मी है और उसके असमान्तर भुजा 130 मी है तो समलम्ब का क्षेत्रफल ज्ञात करें?

(1) 84000 m^2
(2) 8400 m^2
(3) 4200 m^2
(4) 42000 m^2


Q.4:- If/ यदि  ( x + y + z) = 1 ,  xy + yx + zx = - 26, SSC-CGL-MATHS-29-01-2020 , what is the value of/ का मान ज्ञात करें xyz?

(1) -48
(2) 24
(3) 48
(4) -24


Q.5:- How many number are there less than 1400 that are divisible by 5 or 7 but not by 35?

1400 से छोटी कितनी संख्याएं है जो 5 या 7 से विभाजित है परन्तु 35 से विभाजित नहीं है ?


(1) 349
(2) 439
(3) 400
(4) 389


Q.6:- A certain sum amounts to Rs.4205.55 at 15% pa for 2(2/5) year. Interest is being compounded annually?

एक निश्चित धनराशी को 15% प्रतिवर्ष की दर से 2(2/5) में 4205.55 रुपाए हो जाता है तो धन राशी ज्ञात करें

(1) Rs.3600
(2) Rs.3600
(3) Rs. 3404
(4)  Rs. 3000


Q.7:- . If A is 28% more than B and C is 25% less than the sum of the A and B then by what percent will c more than A( correct to the one decimal place)

यदि A, B से  28% ज्यादा है और C, A और B के योग  से 25% कम है C, A से कितना प्रतिशत ज्यादा है 

(1) 32.2%
(2) 33.6%
(3) 28%
(4) 43%


Q.8 :- . In ΔABC, D is the point on side BC such that ADC = BAC. If CA=12 cm, then CD is equal to?

ΔABC में, D, BC की पर एक बिंदु है, जिससे कि ADC = BAC यदि CA=12 सेमी हो तो CD बराबर है?


(1) 15 cm
(2) 12 cm
(3) 16 cm
(4)  18 cm


Q.9:- Anu sold an article for Rs.480 at some profit. Had she sold it for Rs.400, there would have been loss equal to one third of the initial profit. What was the total cost price of the article?

अनु ने कुछ लाभ में ₹ 480 के लिए एक वस्तु को बेचा। अगर उसने इसे ₹ 400 में बेचा होता, तो शुरुआती लाभ के एक तिहाई के बराबर नुकसान होता। वस्तु की कुल लागत मूल्य क्या थी?

(1) Rs.450
(2) Rs.420
(3) Rs.425
(4) Rs.430


Q.10:- If SSC-CGL-MATHS-29-01-2020, then what will be the value of SSC-CGL-MATHS-29-01-2020, correct to one decimal place?

यदि SSC-CGL-MATHS-29-01-2020, तो  SSC-CGL-MATHS-29-01-2020, का मान क्या होगा(दशमलव के एक स्थान तक )?

(1) 8.4
(2) 7.2
(3) 8.2
(4) 7.8









1.Sol:- (4)

As we know, if (a + b + c) = 0
SSC-CGL-MATHS-29-01-2020
SSC-CGL-MATHS-29-01-2020 


2. Sol:-  (4)

L.C.M of 3, 4, 5, 6, 7, and 8 = 840
So required number are in the term of (840n + 2)
Hence largest 4 digit number = (840 x 11 + 2) = 9242
Required sum = 9 + 2 + 4 + 2 = 8


3. Sol:- (4)

Area of trapezium =  ½ (sum of parallel side) x height
= ½ (700) x 120

= 42000 cm^2


4. Sol:- (2)

SSC-CGL-MATHS-29-01-2020
151 – 3xyz = 1(1 + 78)
-3xyz = -151 + 78

= xyz = 24

5. Sol:- (3)
Number less than 1400 that are divisible by 5 =  1400/ 5 – 1 = 280 – 1 = 279
Number less than 1400 that are divisible by 7 = 1400/7 – 1 = 200 – 1 = 199
Number less than 1400 that are divisible by 35 = 1400/35 – 1 = 40 – 1 = 39
Required numbers = (279 – 39 ) + (199 – 39 ) = 240 + 160 = 400


6. Sol: - (4)

Required sum = SSC-CGL-MATHS-29-01-2020

7.Sol. (2)

SSC-CGL-MATHS-29-01-2020
=SSC-CGL-MATHS-29-01-2020


8. Sol. (4)

SSC-CGL-MATHS-29-01-2020
Using similarity – समरूपता से-
SSC-CGL-MATHS-29-01-2020


9. Sol. (2)

= 420

10.Sol. (4)


SSC-CGL-MATHS-29-01-2020

0 comments:

Post a Comment

MAHENDRA GURU

Copyright © 2023 www.mahendraguru.com All Right Reserved by Mahendra Educational Pvt . Ltd.