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SSC CGL & CHSL Quiz : Quantitative Aptitude | 06-01-2020

Durgesh Mahendras
SSC CGL & CHSL Quiz : Quantitative Aptitude | 06-01-2020


As SSC CGL notification is out and candidates have started their preparation for this exam. Mahendras also has started special quizzes for this examination. This series of the quizzes is based on the latest pattern of the SSC CGL examination. Regular practice of the questions included in the quizzes will boost up your preparations and it will be very helpful in scoring good marks in the examination.



Q.1 If SSC-CGL-MATHS-QUIZ-06-01-2020

(1) SSC-CGL-MATHS-QUIZ-06-01-2020
(2) SSC-CGL-MATHS-QUIZ-06-01-2020
(3) 2
(4) 1

Q.2:- A 120 m long train running at a speed of 57 km/hr. from Delhi to Lucknow and another train running at a speed of 69 km/hr. from Lucknow to Delhi with length of x m crossed each other in 8 sec then length of longer train is how much meter more than the length of shorter train?

एक 120 मी लम्बी ट्रेन 57 किमी/घं की चाल से दिल्ली से लखनऊ के लिए चल रही है, एक दूसरी ट्रेन जिसकी लम्बाई x मी है 69 किमी की रफ़्तार से लखनऊ से दिल्ली की और जा रही है दोनों एक दुसरे को 8 सेकेंड में पार करती है तो बड़ी ट्रेन की लम्बाई, छोटी ट्रेन की लम्बाई से कितना ज्यादा है?

(1) 160 m
(2) 40 m
(3) 30m
(4) 45 m

Q.3:- What is the ratio of inradius to circumradius of a triangle whose longest side is 37 cm. If sum and difference of other two sides are 47 and 23 respectively?

त्रिभुज की अन्तः त्रिज्या और बाह्य त्रिज्या का अनुपात क्या होगा यदि उसकी सबसे बड़ी भुजा की लम्बाई 37 सेमी है और अन्य दो भुजाओ की लम्बाई का योग और अंतर क्रमशः 47 और 23 है ?

(1). 10 : 37
(2) 23 : 37
(3) 20 : 37
(4) 20 : 21

Q.4:- There are three numbers. Average of two number is when added to third number the sum is obtained are 177, 163 and 138. what is average of largest and smallest number of them.

तीन संख्याएं दी गयी है, जिनमे जब किन्ही दो संख्या का औसत तीसरी संख्या में जोड़ा जाता है तो उनका योग 177, 163 और 138 प्रप्थोते है तो सबसे बड़ी  संख्या और सबसे छोटी संख्या का औसत ज्ञात करें?

(1) 67
(2) 56
(3) 76
(4) 66
Q.5:- If x + y =  7 and xy = 10 then SSC-CGL-MATHS-QUIZ-06-01-2020 = ?

यदि x + y =  7 और xy = 10 तो SSC-CGL-MATHS-QUIZ-06-01-2020= ?

(1) 0.0609
(2) 0.00609
(3)0.609
(4)0.000609

Q.6:- Find the greatest number of five digits which when divided by 24, 60, 75 and 90 gives remainder 4 in each case.

पाँच अंको की सबसे बड़ी संख्या ज्ञात कीजिए जो 24, 60, 75 और 90 से विभाजित करनें पर प्रत्येक दशा में शेष 4 देता है।

(1) 98904
(2) 99204
(3) 99404
(4) 99004

 Q.7:- Find the number of diagonals in in a polygon having 14 sides.

14 भुजाओं वाले बहुभुज में विकर्णों की संख्या ज्ञात कीजिए।

(1) 66
(2) 77
(3) 78
(4) 69

Q.8:- Find the area of largest circle that can be placed in a right angled triangle having sides 5,12 and 13 cm.

सबसे बड़े वृत्त का क्षेत्रफल ज्ञात करें जिसे समकोण त्रिभुज में रखा जा सकता है जिसकी भुजाएं 5,12 और 13 सेमी हैं।

(1) SSC-CGL-MATHS-QUIZ-06-01-2020
(2)SSC-CGL-MATHS-QUIZ-06-01-2020
(3) SSC-CGL-MATHS-QUIZ-06-01-2020
(4) SSC-CGL-MATHS-QUIZ-06-01-2020

Q.9:-Find the equation of line parallel to 5x+12y=20 and passing through point (5,8).

5x + 12y = 20 के समानांतर रेखा का समीकरण ज्ञात करें जो बिंदु (5,8) से गुजरता हो।

(1) 5x+8y=108
(2) 5x+12y=121
(3) 12y–5x=121
(4) 5x–8y=108

Q.10:- Find the value ofSSC-CGL-MATHS-QUIZ-06-01-2020.

SSC-CGL-MATHS-QUIZ-06-01-2020 का मान ज्ञात कीजिए।

(1) SSC-CGL-MATHS-QUIZ-06-01-2020
(2) SSC-CGL-MATHS-QUIZ-06-01-2020
(3) SSC-CGL-MATHS-QUIZ-06-01-2020
(4) SSC-CGL-MATHS-QUIZ-06-01-2020












Answer:- 



1. Sol:- (3)

Divide equation by SSC-CGL-MATHS-QUIZ-06-01-2020
SSC-CGL-MATHS-QUIZ-06-01-2020
SSC-CGL-MATHS-QUIZ-06-01-2020
SSC-CGL-MATHS-QUIZ-06-01-2020
SSC-CGL-MATHS-QUIZ-06-01-2020
SSC-CGL-MATHS-QUIZ-06-01-2020
SSC-CGL-MATHS-QUIZ-06-01-2020

2.Sol:-  (2)

L1 = 120 m
L2 = x m
S1 = 57 km/hr , S2 = 69 km/ hr
Relative speed = (57 + 69) x (5/18) = 35m/s
SSC-CGL-MATHS-QUIZ-06-01-2020
280 – 120 = x
.x = 160
Required difference = 160 – 120 = 40 m


3.Sol:- (1)

As we know,
12, 35 , 37 are Pythagoreans triplets
Triangle is right angle triangle
Inradius = (12 + 35 – 37 )/ 2 = 10/ 2 = 5
Circumradius = 37/2
Required ratio = 10 : 37

4. Sol:- (3)

2 I + II + III = 354
I + 2 II + III = 326
I + II + 2III = 276
After adding,
4(I + II + III) = 956
I + II + II = 239
III = 37, I = 115, II = 87
Required average = (115 + 37)/ 2 = 76

5. Sol:- (1)

(x – y) = 3
SSC-CGL-MATHS-QUIZ-06-01-2020 = 29
SSC-CGL-MATHS-QUIZ-06-01-2020
= SSC-CGL-MATHS-QUIZ-06-01-2020

6.Sol:- (4) 

LCM (24, 60 , 75 and 90)=1800
Required answer=1800×55+4=99004

7.Sol:- (2) 

Required answer= SSC-CGL-MATHS-QUIZ-06-01-2020
अभीष्ट उत्तर= SSC-CGL-MATHS-QUIZ-06-01-2020

8.Sol:- (4) 

In center= SSC-CGL-MATHS-QUIZ-06-01-2020
Required answer= SSC-CGL-MATHS-QUIZ-06-01-2020


9.Sol:- 

SSC-CGL-MATHS-QUIZ-06-01-2020
So m=–5/12
Required equation of line
SSC-CGL-MATHS-QUIZ-06-01-2020
5x+12y=121
SSC-CGL-MATHS-QUIZ-06-01-2020
अतः m=–5/12
रेखा का अभीष्ट समीकरण
SSC-CGL-MATHS-QUIZ-06-01-2020
5x+12y=121

10.Sol:- (2)

SSC-CGL-MATHS-QUIZ-06-01-2020

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