mahendras

| Join Mahendras Telegram Channel | Like Mahendras Facebook Page | Online Admission | Download Mahendras App

Now Subscribe for Free videos

Subscribe Now

Quantitative Aptitude Quiz For SBI Clerk | 24-02-2020

Swati Mahendra's
Quantitative Aptitude Quiz For SBI Clerk / RBI Assistant | 04-02-2020

Dear Readers,


Mahendras has started special quizzes for SBI Clerk Pre examination so that you can practice more and more to crack the examination. This SBI Clerk Pre special quiz series will mold your preparations in the right direction and the regular practice of these quizzes will be really very helpful in scoring good marks in the Examination.Here we are providing you important question of Quantitative aptitude for SBI Clerk Pre 2020 Exam.

Q-(1-5) What value will come in place of question mark (?) in following questions?

निम्नलिखित संख्या-श्रृंखला में प्रश्नवाचक चिन्ह (?) के स्थान पर क्या मान आयेगा?


(1) 10    42    58   66   70   ? 


(1) 70
(2) 62
(3) 68
(4) 72
(5) 82
 
(2) 5   10   31   76   153   ? 

(1) 252
(2) 240
(3) 263
(4) 270
(5) 280

(3) 15   20   45   140   565    ?

(1) 2530
(2) 2830
(3) 2920
(4) 2650
(5) 2360

(4) 3   4   12   45   196    ? 

(1) 1105
(2) 1010
(3) 1007
(4) 1005
(5) 1008

(5) 1728   2744   4096   5832   8000    10648   ?  
 
(1) 12167
(2) 13824
(3) 15625
(4) 9261
(5) 17576

Q-(6-10) In each of the following questions, two equations (I ) and (II) are given. You have to solve them and state the correct relationship-

निम्नलिखित प्रश्नों में दो समीकरण (I) और (II) दिये गये है दोनों समीकरण हल कीजिए और सही सम्बन्ध स्थापित कीजिए-


(6)   I. 8x2 + 12x - 8 = 0               II. 9y2 + 18y + 9 = 0


(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or the relationship can not be established.

(7) I. http://onlinespeedtest.mahendras.org/Images/140331402898311.png              II. http://onlinespeedtest.mahendras.org/Images/140331403820277.png

(1) x > y
(2) x > y
(3) x < y
(4) x < y
(5) x = y or the relationship can not be established.

(8) A towel, when bleached, was found to have lost 25% of its length and 10% of its breadth. The percentage of decrease in area is-

एक तौलिया, जब ब्लीच की जाती है तो , अपनी लंबाई का 25% और चौड़ाई का 10% खो देती है।  क्षेत्रफल में कितनी कमी आई ?


(1) 30%
(2) 32.5%
(3) 35%
(4) 37.5%
(5) 40%

(9) A rectangular park 55 m long and 45 m wide has two concrete crossroads running in the middle of the park and rest of the park has been used as a lawn. If the area of the lawn is 2091 sq. m, then what is the width of the road?

एक आयताकार पार्क 55 मीटर लंबा और 45 मीटर चौड़ा है जिसके मध्य से जाने वाली दो पथरीली सड़कें एक दूसरे को काटती है  और शेष पार्क को लॉन के रूप में प्रयोग किया जाता है। यदि लॉन का क्षेत्रफल 2091 वर्ग मीटर है, तो सड़क की चौड़ाई क्या है?


(1) 2 m.
(2) 3 m.
(3) 4 m.
(4) 5 m.
(5) 6 m.

(10) In an examination, the number of successful students was 4 times the number of unsuccessful students. If there were 35 less students and the number of unsuccessful students were 9 more, then the ratio of their number would have been 2 : 1. Find the total number of students.

एक परीक्षा में सफल छात्रों की संख्या, असफल छात्रों की संख्या की 4 गुनी थी। यदि 35 छात्र कम होते और असफल छात्रों की संख्या 9 अधिक होती तो इनकी संख्या में 2 : 1 का अनुपात होता। कुल छात्रों की संख्या क्या थी ?


(1) 120

(2) 124
(3) 135
(4) 145
(5) 155


Answer Key-

1-Sol-(4) 

-32, - 16, - 8, - 4, - 2 

2-Sol-(4) 

3-Sol-(2) 

15 × 1 + 5 = 20
20 × 2 + 5 = 45
45 × 3 + 5 = 140
140 × 4 + 5 = 565
565 × 5 + 5 = 2830 

4-Sol-(4) 

3 × 1 + 12 = 4
4 × 2 + 22 = 12
12 × 3 + 33 = 45
45 × 4 + 44 = 196
196 × 5 + 55 = 1005 

5-Sol-(2) 

12 × 12 × 12 =1728
14 × 14 × 14 = 2744
16 × 16 × 16 = 4096
18 × 18 × 18 = 5832
20 × 20 × 20 = 8000 
And so on .....
? = 24 × 24 × 24 = 13824 

6-Sol-(5) 

x = +4 | - 4
y = 1 | -1 
7-Sol-(5) 

7y - 1 =
7y = 14
y = 2
x + = 2+
x = 2
8-Sol-(2) 

Required % = = 32.5% 

9-Sol-(3) 

Let the width of the road is x m.
According to the question-
Area of lawn = {55 x 45 – (55 x + 45 x – x2)}
2091 = 2475 – 100x – x2 
x2 – 100 x – 384 = 0 => (x – 4) (x – 96) = 0
x = 4 because x cannot be equal to 96. 

10-Sol-(5) 

Let the number of unsuccessful student = x
Then number of successful student = 4x
So, total number of student = 5x
According to Question-
{(5 x – 35) – (x + 9)} : (x +9) = 2 : 1
x = 31
so, total number of student = 5 x = 5 x 31 = 155

Copyright © 2023 www.mahendraguru.com All Right Reserved by Mahendra Educational Pvt . Ltd.