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SSC CHSL Quiz : Quantitative Aptitude | 23-04-2020

Priyanka Mahendras
SSC CHSL Quiz : Quantitative Aptitude | 23 -03-2020





As SSC CHSL notification is out and candidates have started their preparation for this exam. Mahendras also has started special quizzes for this examination. This series of the quizzes are based on the latest pattern of the SSC CHSL examination. Regular practice of the questions included in the quizzes will boost up your preparations and it will be very helpful in scoring good marks in the examination.






Q. 1. A man saves 30% of his income in 1 year. If he wants to save the same amount in 8 months, then by how much percentage should he increase his monthly savings?

рдПрдХ рдЖрджрдоी 1 рд╕ाрд▓ рдоें рдЕрдкрдиी рдЖрдп рдХा 30% рдмрдЪाрддा рд╣ै। рдпрджि рд╡рд╣ 8 рдорд╣ीрдиे рдоें рд╕рдоाрди рд░ाрд╢ि рдмрдЪाрдиा рдЪाрд╣рддा рд╣ै, рддो рдЙрд╕े рдЕрдкрдиी рдоाрд╕िрдХ рдмрдЪрдд рдоें рдХिрддрдиे рдк्рд░рддिрд╢рдд рдХी рд╡ृрдж्рдзि рдХрд░рдиी рдЪाрд╣िрдП?

(A) 20

(B) 30

(C) 40

(D) 50

Q. 2. A man spends 80% of his income and saves the rest. If his income and spending both increases by 10%, then what is the percentage change in his savings?

рдПрдХ рдЖрджрдоी рдЕрдкрдиी рдЖрдп рдХा 80% рдЦрд░्рдЪ рдХрд░рддा рд╣ै рдФрд░ рдмाрдХी рдмрдЪा рд▓ेрддा рд╣ै। рдпрджि рдЙрд╕рдХी рдЖрдп рдФрд░ рд╡्рдпрдп рджोрдиों 10% рдмрдв़ рдЬाрддे рд╣ैं, рддो рдЙрд╕рдХी рдмрдЪрдд рдоें рдк्рд░рддिрд╢рдд рдкрд░िрд╡рд░्рддрди рдХ्рдпा рд╣ै?

(A) 10% increase/рд╡ृрдж्рдзि

(B) 5% decrease/рдХрдоी

(C) 5% increase/рд╡ृрдж्рдзि

(D) 15% decrease/рдХрдоी

Q. 3. A car travels at a speed of 25 m/s for 8 hours. What is the distance (in km) travelled by the car?

рдПрдХ рдХाрд░ 8 рдШंрдЯे рдХे рд▓िрдП 25 рдоीрдЯрд░ / рд╕ेрдХंрдб рдХी рдЧрддि рд╕े рдпाрдд्рд░ा рдХрд░рддी рд╣ै। рдХाрд░ рдж्рд╡ाрд░ा рддрдп рдХी рдЧрдИ рджूрд░ी (рдХिрдоी рдоें) рдХिрддрдиी рд╣ै?

(A) 360

(B) 720

(C) 450

(D) 900

Q. 4. A 450 meter long train crosses a bridge 650 meters long in 36 seconds. What is speed (in km/hr) of the train? 

450 рдоीрдЯрд░ рд▓ंрдмी рдЯ्рд░ेрди 36 рд╕ेрдХंрдб рдоें 650 рдоीрдЯрд░ рд▓ंрдмा рдПрдХ рдкुрд▓ рдкाрд░ рдХрд░рддी рд╣ै। рдЯ्рд░ेрди рдХी рдЧрддि (рдХिрдоी / рдШंрдЯा рдоें) рдХ्рдпा рд╣ै?

(A) 110

(B) 125

(C) 150

(D) 95

Q. 5. The population of a town increases at the rate of 15% per annum. If the present population is 108445 of town, then what was the population 2 years ago?

рдПрдХ рд╢рд╣рд░ рдХी рдЬрдирд╕ंрдЦ्рдпा рдк्рд░рддि рд╡рд░्рд╖ 15% рдХी рджрд░ рд╕े рдмрдв़рддी рд╣ै। рдпрджि рд╢рд╣рд░ рдХी рд╡рд░्рддрдоाрди рдЬрдирд╕ंрдЦ्рдпा 108445 рд╣ै, рддो 2 рд╕ाрд▓ рдкрд╣рд▓े рдЖрдмाрджी рдХ्рдпा рдеी?

(A) 72000

(B) 79000

(C) 82000

(D) 85000

Q. 6. The compound interest on a certain sum of money at 3% per annum after 2 years is Rs.487.2. Find the amount of the simple interest obtained on the same sum of money at the same rate of interest after 2 years.

рдПрдХ рдиिрд╢्рдЪिрдд рдзрдирд░ाрд╢ि рдкрд░ рджो рд╡рд░्рд╖ рдХे рдмाрдж 3% рд╡ाрд░्рд╖िрдХ рдм्рдпाрдЬ рдХी рджрд░ рд╕े рдЪрдХ्рд░рд╡ृрдж्рдзि рдм्рдпाрдЬ рд░ु.487.2 рд╣ै । рдЙрд╕ी рдзрдирд░ाрд╢ि рдкрд░ рд╕рдоाрди рдм्рдпाрдЬ рдХी рджрд░ рд╕े 2 рд╡рд░्рд╖ рдХे рдмाрдж рд╕ाрдзाрд░рдг рдм्рдпाрдЬ рдЬ्рдЮाрдд рдХीрдЬिрдпे ।

(A) Rs. / рд░ु. 520

(B) Rs. / рд░ु. 480

(C) Rs. / рд░ु. 490

(D) Rs. / рд░ु. 525

Q. 7. Find mode, using an empirical relation, when it is given that mean and median are 10.5 and 9.6 respectively.

рдмрд╣ुрд▓рдХ рдЬ्рдЮाрдд рдХीрдЬिрдпे, рдПрдо्рдкिрд░िрдХрд▓ рд╕ूрдд्рд░ рдХी рд╕рд╣ाрдпрддा рд╕े, рдЬрдм рдпрд╣ рджिрдпा рдЧрдпा рд╣ै рдХि рдоाрдз्рдп рдФрд░ рдоाрдз्рдпिрдХा рдХ्рд░рдорд╢ः 10.5 рдФрд░ 9.6 рд╣ैं ।

(A) 7.55

(B) 7.6

(C) 7.2

(D) 7.8

Q. 8. Find the value of 2 (sin6q + cos6q) – 3 (sin4q + cos4q).

2 (sin6q + cos6q) – 3 (sin4q + cos4q) рдХा рдоाрди рдЬ्рдЮाрдд рдХीрдЬिрдпे ।

(A) 1

(B) 0

(C) – 1

(D) 2

Q. 9. Two trains, each of length 125 metre, are running in parallel tracks in opposite directions. One train is running in a speed 65 km/hr and they cross each other in 6 seconds. The speed of the other train (in km/hr.) is - 

рдк्рд░рдд्рдпेрдХ 125 рдоीрдЯрд░ рд▓ंрдмी рджो рд░ेрд▓рдЧाреЬिрдпों рд╕рдоांрддрд░ рдкрдЯрд░िрдпों рдкрд░ рд╡िрдкрд░ीрдд рджिрд╢ा рдоें рдЪрд▓ рд░рд╣ी рд╣ैं। рдЙрдирдоें рдПрдХ рд░ेрд▓рдЧाреЬी 65 рдХिрдоी. /рдШं. рдХी рдЧрддि рд╕े рдЪрд▓ рд░рд╣ीं рд╣ै рдФрд░ рд╡े рджोрдиों рдПрдХ-рджूрд╕рд░े рдХो 6 рд╕ेрдХрдг्рдб рдоें рдкाрд░ рдХрд░ рд▓ेрддी рд╣ैं । рддрджрдиुрд╕ाрд░, рджूрд╕рд░ी рд░ेрд▓рдЧाреЬी рдХी рдЧрддि (рдХिрдоी/рдШंрдЯे рдоें) рд╣ै -

(A) 85

(B) 75

(C) 80

(D) 70

Q. 10. Meena, Manita and Mamta started a business. 40% of the total investment was investment by Meena and Mamta invested (2/3) of the total sum invested by Meena and Manita. If Manita invested (1/5) of the total investment then what will be the share of Mamta in the total profit of Rs.8855.

рдоीрдиा, рдордиीрддा рдФрд░ рдордорддा рдиे рдПрдХ рд╡्рдпрд╡рд╕ाрдп рд╢ुрд░ू рдХिрдпा । рдХुрд▓ рдиिрд╡ेрд╢ рдХा 40% рдоीрдиा рдж्рд╡ाрд░ा рдиिрд╡ेрд╢ рдХिрдпा рдЧрдпा рдеा рдФрд░ рдордорддा рдиे рдоीрдиा рдФрд░ рдордиीрддा рдж्рд╡ाрд░ा рдиिрд╡ेрд╢ рдХी рдЧрдпी рдХुрд▓ рд░ाрд╢ि рдХा рджो рддिрд╣ाрдИ рдиिрд╡ेрд╢ рдХिрдпा । рдпрджि рдордиीрддा рдиे рдХुрд▓ рдиिрд╡ेрд╢ рдХा 1/5 рд╣िрд╕्рд╕ा рдиिрд╡ेрд╢ рдХिрдпा рддो рдордорддा рдХा 8855 рд░ुрдкрдпे рдХे рдХुрд▓ рд▓ाрдн рдоें рдХ्рдпा рд╣िрд╕्рд╕ा рд╣ै?

(A) Rs. / рд░ु. 3542

(B) Rs. / рд░ु. 3238

(C) Rs. / рд░ु. 2828

(D) Rs. / рд░ु. 3628

Answer key:


1. Sol. (D)

Let monthly income of man/ рдЖрджрдоी рдХी рдоाрд╕िрдХ рдЖрдп = Rs. / рд░ु. 100
=> Monthly savings/ рдоाрд╕िрдХ рдмрдЪрдд = (30/100) × 100 = Rs. / рд░ु. 30
Yearly savings/ рд╡ाрд░्рд╖िрдХ рдмрдЪрдд = 30 × 12 = Rs. / рд░ु. 360
Now, income in 8 months/ рдЕрдм, 8 рдорд╣ीрдиे рдоें рдЖрдп = Rs. / рд░ु. 800
Saving the same amount, his new monthly savings/ рдЙрд╕ी рд░ाрд╢ि рдХी рдмрдЪрдд, рдЙрд╕рдХी рдирдИ рдоाрд╕िрдХ рдмрдЪрдд
= (360/800) × 100 = Rs. / рд░ु. 45
Increase in monthly savings/ рдоाрд╕िрдХ рдмрдЪрдд рдоें рд╡ृрдж्рдзि = [(45 – 30)/30] ×100
= (15/3) × 10 = 50%

2. Sol. (A)
Let income of man/рдоाрдиा рдЖрджрдоी рдХी рдЖрдп = Rs. / рд░ु. 100
Money spent/ рдкैрд╕ा рдЦрд░्рдЪ = (80/100) × 100 = Rs. / рд░ु. 80
=> Money saved/ рдзрди рдмрдЪाрдпा =
If his income and spending both increases by 10%/ рдпрджि рдЙрд╕рдХी рдЖрдп рдФрд░ рд╡्рдпрдп рджोрдиों 10% рдмрдв़ рдЬाрддे рд╣ैं,
=> New income/ рдирдИ рдЖрдп = 100 + [(10/100) × 100] = Rs. / рд░ु. 110
and new amount spent/ рдФрд░ рдЦрд░्рдЪ рдХी рдЧрдИ рдирдИ рд░ाрд╢ि = 80 + [(10/100) × 80] = Rs. / рд░ु. 88
=> Money saved/ рдкैрд╕ा рдмрдЪाрдпा = (110 − 88) = Rs. / рд░ु. 22
Percentage increase in his savings/ рдЙрд╕рдХी рдмрдЪрдд рдоें рдк्рд░рддिрд╢рдд рд╡ृрдж्рдзि
= [(22 – 20)/20] × 100 = 2 × 5 = 10%

3. Sol. (B)
Speed of car/ рдХाрд░ рдХी рдЧрддि = 25 m/s = [25 × (18/5)] = 90 km/hr. / рдХिрдоी / рдШंрдЯा.
Time taken/ рд╕рдордп рд▓िрдпा рдЧрдпा = 8 hours/рдШंрдЯे
=> Distance covered/рддрдп рдХी рдЧрдпी рджूрд░ी = speed/ рдЧрддि × time/ рд╕рдордп
= 90 × 8 = 720 km/ рдХिрдоी

4. Sol. (A)
Length of train/ рдЯ्рд░ेрди рдХी рд▓ंрдмाрдИ = 450 m/ рдоीрдЯрд░
and length of bridge/ рдоीрдЯрд░ рдФрд░ рдкुрд▓ рдХी рд▓ंрдмाрдИ = 650 m/ рдоीрдЯрд░
Time taken/рд▓िрдпा рдЧрдпा рд╕рдордп = 36 seconds/рд╕ेрдХेрдг्рдб
=> Speed/ рдЧрддि = distance/time/ рджूрд░ी / рд╕рдордп
= [(450 + 650)/36]
= 1100/36 = 275/9 m/s/ рдоी. / рд╕े.
= (275/9) × (18/5) km/hr/ рдХिрдоी / рдШंрдЯा = 55 × 2 = 110 km/hr/ рдХिрдоी / рдШंрдЯा

5. Sol. (C)

Let population 2 years ago/ 2 рд╡рд░्рд╖ рдкрд╣рд▓े рдЬрдирд╕ंрдЦ्рдпा = 100x
Population after 1st year increasing by 15%/1 рд╡рд░्рд╖ рдХे рдмाрдж рдЬрдирд╕ंрдЦ्рдпा рдоें 15% рдХी рд╡ृрдж्рдзि
= 100x × (105/100) = 132.25x
Population after 2nd year/2 рд╡рд░्рд╖ рдХे рдмाрдж рдЬрдирд╕ंрдЦ्рдпा = 115 × (115/100) = 132.25x
According to question/ рдк्рд░рд╢्рдиाрдиुрд╕ाрд░,
=> 132.25x = 108445
x = 108445/132.25 = 820
Population 2 years ago/ 2 рд╡рд░्рд╖ рдкрд╣рд▓े рдЬрдирд╕ंрдЦ्рдпा = 100 × 820 = 82000

6. Sol. (B)

Let the sum of money be Rs. 10000. /рдоाрдиा рдзрдирд░ाрд╢ि рд░ु. 10000 рд╣ै ।
C.I. /рдЪрдХ्рд░рд╡ृрдж्рдзि рдм्рдпाрдЬ = 300 + 300 + 9 = 609
According to the question/рдк्рд░рд╢्рдиाрдиुрд╕ाрд░,
609 = 487.2
1 = 0.8
10000 = 8000
Required S.I. /рдЕрднीрд╖्рдЯ рд╕ाрдзाрд░рдг рдм्рдпाрдЬ = (8000 × 2 × 3)/100 = Rs. / рд░ु. 480

7. Sol. (D)
Mean/ рдоाрдз्рдп = 10.5 and/рдФрд░ median/ рдоाрдз्рдпिрдХा = 9.6
Empirical relation/ рдПрдо्рдкीрд░िрдХрд▓ рд╕ूрдд्рд░ рд╕े:
3 Median/ рдоाрдз्рдпिрдХा = Mode/ рдмрд╣ुрд▓рдХ + 2 Mean/ рдоाрдз्рдп
3(9.6) = Mode/ рдмрд╣ुрд▓рдХ/ + 2(10.5)
28.8 = Mode/ рдмрд╣ुрд▓рдХ + 21
Mode/ рдмрд╣ुрд▓рдХ = 28.8 – 21 = 7.8

8. Sol. (C)
2 (sin6q + cos6q) – 3 (sin4q – cos4q)
= 2 {(sin2q + cos2q)3 – 3 sin2q cos2q (sin2q + cos2q)} – 3 {(sin2q + cos2q)2 – 2 sin2q cos2q}
= 2 – 6 sin2q cos2q – 3 + 6 sin2q cos2q
= – 1

9. Sol. (A)
(250/6) × (18/5) = 65 + A
A = 85



10. Sol. (A)

Meena/ рдоीрдиा Manita/ рдордиीрддा Mamta/ рдордорддा
40 20 40
Ratio/ рдЕрдиुрдкाрдд = 2 : 1 : 2
Required value/ рдЕрднीрд╖्рдЯ рдоाрди = (2/5) × 8855 = Rs. / рд░ु. 3542

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