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SSC CHSL Quiz : Quantitative Aptitude |15-06-2020

Priyanka Mahendras


SSC CHSL Quiz : Quantitative Aptitude | 23 -03-2020





As SSC CHSL notification is out and candidates have started their preparation for this exam. Mahendras also has started special quizzes for this examination. This series of the quizzes are based on the latest pattern of the SSC CHSL examination. Regular practice of the questions included in the quizzes will boost up your preparations and it will be very helpful in scoring good marks in the examination.

Q. 1. 20 buckets of water fill a tank when the capacity of each bucket is 14.5 litres. How many buckets will be required to fill the same tank if the capacity of each bucket is 10 litres?
рдкाрдиी рдХी 20 рдмाрд▓्рдЯिрдпां рдПрдХ рдЯंрдХी рдХो рднрд░ рджेрддी рд╣ैं, рдЬрдмрдХि рдк्рд░рдд्рдпेрдХ рдмाрд▓्рдЯी рдХी рдзाрд░िрддा 14.5 рд▓ीрдЯрд░ рд╣ै рдпрджि рдк्рд░рдд्рдпेрдХ рдмाрд▓्рдЯी рдХी рдзाрд░िрддा 10 рд▓ीрдЯрд░ рд╣ो рддो рдЯंрдХी рдХो рднрд░рдиे рдХे рд▓िрдП рдХिрддрдиी рдмाрд▓्рдЯिрдпों рдХी рдЖрд╡рд╢्рдпрдХрддा рд╣ोрдЧी?
(A) 31
(B) 29
(C) 32
(D) 30
Q. 2. The price of an article is raised by 30% and then two successive discounts of 10% each are allowed, ultimately the price of the article is -
рдПрдХ рд╡рд╕्рддु рдХा рдоूрд▓्рдп 30% рдмреЭा рджिрдпा рдЬाрддा рд╣ै рдФрд░ рдлिрд░ рдЙрд╕ рдкрд░ 10% рдХी рджो рдХ्рд░рдоिрдХ рдЫूрдЯ рджी рдЬाрддी рд╣ै рдЕंрдд рдоें рдЙрд╕ рдХा рдоूрд▓्рдп рд╣ो рдЬाрдПрдЧा-
(A) Increased by 10%/10% рдХी рд╡ृрдж्рдзि
(B) Increased by 5.3%/5.3% рдХी рд╡ृрдж्рдзि
(C) Decreased by 3%/3% рдХी рдХрдоी
(D) Decreased by 5.3%/5.3% рдХी рдХрдоी
Q. 3. A sum of Rs. 12000 is to be distributed among A, B and C in the ratio 4: 5: 6. What will be the difference between A's and C's shares?
12000 рд░ू. рдХो A, B рдФрд░ C рдоें 4: 5: 6 рдХे рдЕрдиुрдкाрдд рдоें рдмांрдЯा рдЬाрддा рд╣ै A рдФрд░ C рдХे рднाрдЧों рдоें рдЕंрддрд░ рдХ्рдпा рд╣ै?
(A) Rs.1600
(B) Rs.1000
(C) Rs.1200
(D) Rs.800
Q. 4. In 4 years, the simple interest on a certain sum of money is (7/25) of the principal. The annual rate of interest is-
4 рд╡рд░्рд╖ рдоें рдХिрд╕ी рдзрдирд░ाрд╢ि рдкрд░ рд╕ाрдзाрд░рдг рдм्рдпाрдЬ рдЙрд╕ी рдзрдирд░ाрд╢ि рдХा (7/25) рдк्рд░ाрдк्рдд рд╣ोрддा рд╣ै рддो рд╡ाрд░्рд╖िрдХ рдм्рдпाрдЬ рджрд░ рд╣ै-
(A) 12.5%
(B) 7%
(C) 10%
(D) 8%
Q. 5. How many seconds will an 800 m long train take to cross a man walking with a speed of 4 km/hr. in the direction of the moving train if the speed of train is 64 km/hr.?
800 рдоीрдЯрд░ рд▓рдо्рдмी рдПрдХ рд░ेрд▓рдЧाреЬी рдХो 4 рдХिрдоी/рдШं. рдХी рдЪाрд▓ рд╕े рдЙрд╕рдХी рджिрд╢ा рдоें рдкैрджрд▓ рдЪрд▓рддे рд╡्рдпрдХ्рддि рдХो рдкाрд░ рдХрд░рдиे рдоें рдХिрддрдиा рд╕рдордп (рд╕ेрдХрдг्рдб рдоें) рд▓рдЧेрдЧा, рдпрджि рд░ेрд▓рдЧाреЬी 64 рдХिрдоी/рдШंрдЯे рдХी рдЪाрд▓ рд╕े рдЪрд▓ рд░рд╣ी рд╣ै?
(A) 30 seconds/рд╕ेрдХрдг्рдб
(B) 36 seconds/рд╕ेрдХрдг्рдб
(C) 48 seconds/рд╕ेрдХрдг्рдб
(D) 42 seconds/рд╕ेрдХрдг्рдб
Q. 6. A phone is sold for Rs. 860 at a loss of 20% for how much should it be sold gain 10%?
рдПрдХ рдлोрди 860 рд░ूрдкрдП рдоें рдмेрдЪрдиे рдкрд░ 20% рдХी рд╣ाрдиि рд╣ोрддी рд╣ै рдЙрд╕ 10% рд▓ाрдн рдХрдоाрдиे рдХे рд▓िрдП рдЙрд╕े рдХिрддрдиे рдоें рдмेрдЪрдиा рдЪाрд╣िрдП?
(A) Rs.1182.5
(B) Rs.1168.5
(C) Rs.1092.5
(D) Rs.1220.5
Q. 7. The selling price of 15 articles is same as the cost price of 13 articles. The gain or loss is-
15 рд╡рд╕्рддुрдУं рдХा рд╡िрдХ्рд░рдп рдоूрд▓्рдп 13 рд╡рд╕्рддुрдУं рдХे рдХ्рд░рдп рдоूрд▓्рдп рдХे рдмрд░ाрдмрд░ рд╣ै рддो рд▓ाрдн рдпा рд╣ाрдиि рд╣ै-
(A) 20 (1/3) % profit/рд▓ाрдн
(B) 13 (1/3) % profit/рд▓ाрдн
(C) 13 (1/3) % loss/рд╣ाрдиि
(D) 13 (2/3) % loss/рд╣ाрдиि
Q. 8. If x = k3 – 3k2 and y = 1 – 3k, then for what value of k, will be x = y?
рдпрджि x = k3 – 3k2 рдФрд░ y = 1 – 3k, рддो k рдХे рдХिрд╕ рдоाрди рдХे рд▓िрдП x = y рд╣ोрдЧा?
(A) 0
(B) 1
(C) – 1
(D) 2
Q. 9. The marked price of an article is Rs. 500. A shopkeeper gives a discount of 5% and still makes a profit of 25%. The cost price of the article is:
рдПрдХ рд╡рд╕्рддु рдХा рдЕंрдХिрдд рдоूрд▓्рдп рд░ू 500 рд╣ै। рджुрдХाрдирджाрд░ 5% рдХी рдЫूрдЯ рджेрддा рд╣ै рдФрд░ рдлिрд░ рднी 25% рдХा рд▓ाрдн рдХрдоाрддा рд╣ै। рд╡рд╕्рддु рдХा рдХ्рд░рдп рдоूрд▓्рдп рд╣ै:
(A) Rs.384
(B) Rs.380
(C) Rs.300
(D) Rs.376
Q. 10. A can do a piece of work in 12 days and B in 15 days. They work together for 5 days and then B left. The days taken by A to finish the remaining work is:
A рдПрдХ рдХाрдо рдХो 12 рджिрди рдоें рдФрд░ B, 15 рджिрди рдоें рдХрд░ рд╕рдХрддा рд╣ै । рд╡े рдоिрд▓рдХрд░ 5 рджिрди рдХाрдо рдХрд░рддे рд╣ैं рдФрд░ рдлिрд░ B рдХाрдо рдЫोреЬ рджेрддा рд╣ै। A рдж्рд╡ाрд░ा рд╢ेрд╖ рдХाрдо рдХो рдкूрд░ा рдХрд░рдиे рдХे рд▓िрдП рдХिрддрдиे рджिрди рд▓िрдП рдЧрдП?
(A) 3
(B) 5
(C) 10
(D) 12
Answer key:
1. Sol. (C)
Required number of buckets/рдЕрднीрд╖्рдЯ рдмाрд▓्рдЯिрдпों рдХी рд╕ंрдЦ्рдпा = {(20 × 14.5)/ 10} = 29
2. Sol. (B)
Two successive discounts of 10%/10% рдХी рджो рдХ्рд░рдоिрдХ рдЫूрдЯ
= – 10 – 10 + [{(– 10) × (– 10)}/ 100] = – 19%
Resultant/рдкрд░िрдгाрдоी = + 30 – 19 + {30 × (– 19)}/ 100
= 11 – 5.7 = 5.3%
3. Sol. (A)
Required difference/рдЕрднीрд╖्рдЯ рдЕрди्рддрд░ = {12000/ (4 + 5 + 6)} × (6 – 4)
= Rs. 1600
4. Sol. (B)
{(P × 4 × R)/ 100} = (7/25) R
R = 7%
5. Sol. (C)
Relative speed of the train with respect to speed of the man/ рд╡्рдпрдХ्рддि рдХी рдЪाрд▓ рдХे рд╕ाрдкेрдХ्рд╖ рд░ेрд▓рдЧाреЬी рдХी рдЪाрд▓ = 64 – 4 = 60 min/hr. /рдоिрдирдЯ/ рдШंрдЯा
The time taken by the train in crossing then = The time taken in moving a distance equivalent to the length of the train, i.e. 800 m. at 60 km/hr.
рд░ेрд▓рдЧाреЬी рдж्рд╡ाрд░ा рд╡्рдпрдХ्рддि рдХो рдкाрд░ рдХрд░рдиे рдХा рд╕рдордп
 = рд░ेрд▓рдЧाреЬी рдХी рд▓рдо्рдмाрдИ рдХे рдмрд░ाрдмрд░ рдХी рджूрд░ी рдкाрд░ рдХрд░рдиे рдХा рд╕рдордп рдЕрд░्рдеाрдд् 800 рдоी. рдХी рджूрд░ी 60 рдХिрдоी/рдШं. рдЪрд▓рдиे рдХा рд╕рдордп
S = 60 × (5/18) m. / sec /рдоी. /рд╕े.
T = (800/60) × (18/5) = 48 sec/рд╕े.
6. Sol. (A)
Required selling price/рдЕрднीрд╖्рдЯ рд╡िрдХ्рд░рдп рдоूрд▓्рдп = 860 × (100/80) × (110/ 100) = 1182.5
7. Sol. (C)
Loss/рд╣ाрдиि % = {(15 – 13)/ 15} × 100 = (2/15) × 100 = 13 (1/3) %
8. Sol. (B)
x = k3 – 3k2, y = 1 – 3k
k3 – 3k2 = 1 – 3k
k3 – 3k2 + 3k -1 = 0
k3 – 1 – 3k (k – 1) = 0
(k – 1)3 = 0
k = 1
9. Sol. (B)
SP of article/рд╡рд╕्рддु рдХा рд╡िрдХ्рд░рдп рдоूрд▓्рдп = {500 × 95}/ 100 = 475
25 = {(475 – cp)/ cp} × 100
125 CP/рдХ्рд░рдп рдоूрд▓्рдп = Rs.47500
CP/рдХ्рд░рдп рдоूрд▓्рдп = Rs.380
10. Sol. (A)
A ……… 12              5
                        60         
B ……… 15              4
According to the question/рдк्рд░рд╢्рдиाрдиुрд╕ाрд░,
5(5 + 4) + 5x = 60
5x = 60 – 45
5x = 15
x = 3



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