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SSC CPO Quiz : Quantitative Aptitude | 18-11-2020

Swati Mahendras



Dear Readers,

As SSC CPO notification is out and candidates have started their preparation for this exam. Mahendras also has started special quizzes for this examination. This series of the quizzes are based on the latest pattern of the CPO examination. Regular practice of the questions included in the quizzes will boost up your preparations and it will be very helpful in scoring good marks in the examination.


(1) If cos╬╕ + sec╬╕ = 2 (00 <╬╕ <900) then cos10╬╕ + sec11╬╕= ?


рдпрджि cos╬╕ + sec╬╕ = 2 (0
0 <╬╕ <900) рд╣ो рддो cos 10╬╕ + sec 11
╬╕ = ?

(A) 0

(B) 1

(C) 2

(D) -1

(2) Consider those number between 300 and 400 such that when each number is divided by 6, 9 and 12, it leaves 4 as remainder in each cases. What is the sum of the numbers?

300 рдФрд░ 400 рдХे рдмीрдЪ рдЙрди рд╕ंрдЦ्рдпाрдУं рдкрд░ рд╡िрдЪाрд░ рдХीрдЬिрдП рдЬिрди्рд╣ें рдХि 6, 9 рдФрд░ 12 рд╕े рд╡िрднाрдЬिрдд рдХрд░рдиे рдкрд░ рдк्рд░рдд्рдпेрдХ рдоें 4 рд╢ेрд╖рдлрд▓ рдмрдЪे। рд╕ंрдЦ्рдпाрдУें рдХा рдпोрдЧ рдХ्рдпा рд╣ै?


(A) 692

(B) 764

(C) 1080

(D) 1092

(3) A train with a uniform speed passes a platform, 122 m. long, in 17 sec and a bridge 210 meters long in 25 seconds.Find the speed of the train.

рдПрдХ рдЯ्рд░ेрди 122 рдоी.рд▓рдо्рдмा рдк्рд▓ेрдЯрдлाрд░्рдо 17 рд╕ेрдХंрдб рдоें рдФрд░ 210 рдоी. рд▓рдо्рдмा рдкुрд▓ 25 рд╕ेрдХंрдб рдоें рдкाрд░ рдХрд░рддी рд╣ैं। рдЯ्рд░ेрди рдХी рдЪाрд▓ рдЬ्рдЮाрдд рдХीрдЬिрдпे।


(A) 37.6 km/hr. / рдХिрдоी/рдШंрдЯा

(B) 41.5 km/hr. / рдХिрдоी/рдШंрдЯा

(C) 46.5 km/hr. / рдХिрдоी/рдШंрдЯा

(D) 39.6 km/hr. / рдХिрдоी/рдШंрдЯा

(4) D and E are the mid points of two cords AB and AC of a circle with a centre O. The line OD and OE are produced to meet the circle respectively at the point F and G. H is a point on the major arc between F and G of circle. If ∠BAC = 40o , then ∠ FHG=?

O рдХेंрдж्рд░ рд╡ाрд▓े рд╡ृрдд्рдд рдХी рджो рдЬीрд╡ाрдПं AB рдФрд░ AC рдХे рдордз्рдп рдмिंрджु D рдФрд░ E рд╣ै |рд░ेрдЦाрдПं OD рдФрд░ OE рдЖрдЧे рдмреЭрддे рд╣ुрдП рд╡ृрдд्рдд рдХे рдмिंрджु F рдФрд░ G рдкрд░ рдоिрд▓рддी рд╣ै | рд╡ृрдд्рдд рдХे рд╡ृрд╣рдж् рдЪाрдк F рдФрд░ G рдкрд░ рдПрдХ рдмिंрджु H рд╣ै | рдпрджि ∠BAC = 40o , рддрдм ∠ FHG=?

(A) 75


(B) 70


(C) 65
 

(D) 80


(5) A freight ship bares 4 tonnes of weight in 1 day such type of 4 freight ship bares 128 tonnes in 8 days , then how many days 540 tonnes weight bares by 6 freight hip each bares 4 tons weight perday?

рднाрд░рд╡ाрд╣рдХ рдЬрд╣ाрдЬ 1 рджिрди рдоे 4 рдЯрди рдоाрд▓ рдвोрддा рд╣ै рдЗрд╕ीрдк्рд░рдХाрд░ рдХे 4 рдЬрд╣ाрдЬ 8 рджिрди рдоे 128 рдЯрди рднाрд░ рдвोрддे рд╣ै рддो рдЬ्рдЮाрдд рдХीрдЬिрдП рдХिрддрдиे рджिрдиों рдоे 540 рдЯрди рднाрд░, 6 рднाрд░рд╡ाрд╣рдХ рдЬрд╣ाрдЬ рд╕े рдвोрдпा рдЬाрдпेрдЧा рдЬोрдХि рдк्рд░рдд्рдпेрдХ рдк्рд░рддि рджिрди 3 рдЯрди рднाрд░ рдвोрддे рд╣ै ?


(A) 22.5

(B) 25

(C) 30

(D) 32

(6) A rectangular box P is inscribed in a sphere of radius r cm. The surface area of P is 384 cm2. and the sum of the length of its 12 edges is 112 cm. Then r (in cm.) is equal to-

рдПрдХ рдЖрдпрддाрдХाрд░ рдмाрдХ्рд╕ P, рдПрдХ r рд╕ेрдоी. рдд्рд░िрдЬ्рдпा рд╡ाрд▓े рдЧोрд▓े рдоें рдЦींрдЪा рдЬाрддा рд╣ै। P рдХा рдкृрд╖्рдаीрдп рдХ्рд╖ेрдд्рд░рдлрд▓ 384 рд╕ेрдоी2. рд╣ै рдФрд░ рдЗрд╕рдХे 12 рдХोрд░ो рдХी рд▓рдо्рдмाрдИ рдХा рдпोрдЧ 112 рд╕ेрдоी. рд╣ै, рддो r (рд╕ेрдоी. рдоें) рдмрд░ाрдмрд░ рд╣ै-

(A) 8

(B) 10

(C) 12

(D) 14

(7) Find the greatest number which on dividing 152, 277 and 427 leaves equal remainder

152 277 рдФрд░ 427 рдХो рд╡िрднाрдЬिрдд рдХрд░рдиे рд╡ाрд▓ी рд╕рдмрд╕े рдмреЬी рд╕ंрдЦ्рдпा рдЬ्рдЮाрдд рдХीрдЬिрдП, рдЬिрд╕рд╕े рдк्рд░рдд्рдпेрдХ рдмाрд░ рдмрд░ाрдмрд░ рд╢ेрд╖рдлрд▓ рдмрдЪे


(A) 25

(B) 28

(C) 29

(D) 24

(8) The lines 2x+3y = 7 and 3x + 5y = 11intersect of the point

рд░ेрдЦाрдПं 2x+3y = 7 рдФрд░ 3x + 5y = 11 рдПрдХ -рджूрд╕рд░े рдХो рдХाрдЯрддी рд╣ै-

(A) (2,1)

(B) (1,2)

(C) (3,0)

(D) (0,2)

(9) A mixture contains 80% acid and rest water. Part of the mixture that should be removed and replaced by the same amount of water to make the ratio of acid and water 4 : 3 is :

рдПрдХ рдоिрд╢्рд░рдг рдоें 80 % рдЕрдо्рд▓ рд╣ै рдФрд░ рдмाрдХि рдкाрдиी рд╣ै . рддो рдоिрд╢्рд░рдг рд╕े рдХिрддрдиा рднाрдЧ рдиिрдХाрд▓ा рдЬाрдпे рдФрд░ рд╕рдоाрди рдоाрдд्рд░ा рдоे рдкाрдиी рдоिрд▓ाрдпा рдЬाрдпे рдХी рдоिрд╢्рд░рдг рдоें рдЕрдиुрдкाрдд 4 : 3 рд╣ो рдЬाрдпे ?


(A) 1/3

(B) 3/7

(C) 2/3

(D) 2/7

(10) If (x+y-z)2 +(y+z-x)2+(z+x-y)2=0, then the value of x+y-z is-

рдпрджि (x+y-z)2 +(y+z-x)2+(z+x-y)2=0, рддो x+y-z рдХा рдоाрди рдЬ्рдЮाрдд рдХीрдЬिрдпे -


(A) 0

(B) 1

(C) 2

(D) √2

Answer Key-

Q-(1) Sol-(C)

cos╬╕ + sec╬╕ = 2

cos╬╕ + 1/cos╬╕ = 2

cos
2 ╬╕+ 1 - 2cos╬╕ = 0

(cos╬╕ - 1)
2  = 0

cos╬╕ = 1

╬╕ = 0

cos
10╬╕ + sec11╬╕

= 1 + 1 = 2

Q-(2) Sol-(A)

LCM of 6, 9, 12 = 36

Number is the form of 36 p + 4.

Required number for P = 9, 10

Required sum = (36×9+4)+ (36×10+4)

= 328 + 364 = 692

Q-(3) Sol-(D)



Q-(4) Sol-(B)




Q-(6) Sol-(B)



Q-(8) Sol-(A)




Q-(9) Sol-(D)


4 : 1

4 : 3

so difference is 2 / рддो рдЕрдиुрдкाрдд рдХा рдЕंрддрд░ рд╣ै 2

so part of mixture replaced is 2/7

Q-(10) Sol-(C)

(x+y-z)
2 +(y+z-x)2+(z+x-y)2=0,

.' . x+y-z = 0

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