Quantitive Aptitude Quiz For IBPS & SBI Exam | 12 -01-2021

 Dear Readers,

Mahendras has started special quizzes for IBPS & SBI Exam so that you can practice more and more to crack the examination. This IBPS & SBI Exam special quiz series will mold your preparations in the right direction and the regular practice of these quizzes will be really very helpful in scoring good marks in the Examination. Here we are providing you the important question of reasoning ability for the the IBPS & SBI Exam.

Q-(1-5) What value will come in place of question mark (?) in the number series given below?

निम्न दी गयी संख्या श्रृंखला में प्रश्नवाचक चिह्न (?) के स्थान पर क्या मान आएगा ?

(1) 25 26 11 36 5 ?

(1) 12

(2) 45

(3) 33

(4) 31

(5) 30

(2) 1 2 20 ? 35152

(1) 549

(2) 413

(3) 632

(4) 544

(5) 339

(3) 1.5 5 20 74 215 ?

(1) 422

(2) 329

(3) 431

(4) 517

(5) 628

(4) 8 17.5 ? 78.5 161.5 328.5

(1) 37.5

(2) 25

(3) 28

(4) 27.5

(5) 32.75

(5) 7 4 6 21 135 ?

(1) 940

(2) 1020

(3) 1200

(4) 750

(5) 800

Q-(6-10) In each of the following questions, two equations (I) and (II) are given. You have to solve them and Give answer:

निम्नलिखित प्रश्नों में दो समीकरण (I) और (II) दिये गये है दोनों समीकरण हल कीजिए और-

(6) (I) 2x²  - 11x + 15 = 0    (II) 2y²  - 15y + 28 = 0

(1) If x > y

(2) If x>  y

(3) If x < y

(4) If x  <  y

(5) If x = y or relationship cannot be established

(7) (I)        (II) 16y²  - 40y + 25 = 0

(1) If x > y

(2) If x>  y

(3) If x < y

(4) If x  <  y

(5) If x = y or relationship cannot be established

(8) (I) 4x²  + 9 - 12x = 0            (II) 64y² - 80y + 25 = 0

(1) If x > y

(2) If x >  y

(3) If x < y

(4) If x <  y

(5) If x = y or relationship cannot be established

(9) (I) 34x2 + 11x = 3                 (II) 51y2 - 77y + 12 = 0

(1) If x > y

(2) If x >  y

(3) If x < y

(4) If x  <  y

(5) If x = y or relationship cannot be established

(10) (I) 3x²  - 16x + 21 = 0             (II) 6y²  - 25y + 21 = 0

(1) If x > y

(2) If x >  y

(3) If x < y

(4) If x < y

(5) If x = y or relationship cannot be established

Answer Key-

Q-(1) Sol-(5)

×1+1,÷2-2,×3+3,÷4-4,×5+5

Q-(2) Sol-(1)

×1³+1² ,×2³ +2² , ×3³+3² , ×4³+4² 

Q-(3) Sol-(1)

×6-4, ×5-5, ×4-6, ×3-7, ×2-8

Q-(4) Sol-(1)

×2+1.5, ×2+2.5, ×2+3.5, ...

Q-(5) Sol-(3)

×1-3, × 3- 6, × 5 -9, × 7-12, ×9 – 15

Q-(6) Sol-(3)

x = 3 , 2.5,y = 4 , 3.5

x < y

Q-(7) Sol-(1)

x = 2.50

y = 1.25 , 1.25

x > y

Q-(8) Sol-(1)

x = 1.5 , 1.5

y = 0.625 , 0.625

x > y

Q-(9) Sol-(4)

Q-(10) Sol-(5)

x = 3 , 2.33

y = 3 , 1.16

Relationship cannot be established