Quantitative Aptitude Quiz For IBPS & SBI Exam | 19-10-2021

 

Dear Readers,

Mahendras has started special quizzes for IBPS & SBI Exam so that you can practice more and more to crack the examination. This IBPS & SBI Exam special quiz series will mold your preparations in the right direction and the regular practice of these quizzes will be really very helpful in scoring good marks in the Examination. Here we are providing you the important question of reasoning ability for the for the the IBPS & SBI Exam.

(1) In how many ways can letter of the word MAILINGS arrange so that M and N always come together?

कितने विभिन्न प्रकार से शब्द MAILINGS के अक्षरों को व्यवस्थित किया जाये की M और N सदैव एकसाथ आये?

(1) 5040 

(2) 10080 

(3)40320 

(4)20160 

(5) 30240

(2) A man read 2/5 part of a book in 1st day, 34% in second day and remaining page in next two days. In two days he read equal number of page. If he read 52 page on last day, then find out how many page did the book contain?

एक व्यक्ति पहले दिन किसी किताब का 2/5 भाग, दूसरे दिन 34% और शेष भाग को अगले दो दिनों में पढता है। यदि उसने दो दिनों में समान पेजों की संख्या को पढ़ा। और अंतिम दिन में पढ़े गए पेजों की संख्या 52 थी, तो किताब में पेजों की संख्या क्या थी ?

(1) 500 

(2) 560 

(3) 510 

(4) 460 

(5) 400

(3) In a school, number of girls is 75% of number of boys. Difference between boys and girls is 30. On a particular day 20% girls were absent, then find the number of girls those who present?

एक स्कूल में लड़कियों की संख्या, लड़कों की संख्या का 75% है।लड़कों और लड़कियों की संख्या के बीच अंतर 30 है। किसी दिन 20% लड़कियां अनुपस्थित थी, तो उपस्थित लड़कियों की संख्या ज्ञात कीजिये ?

(1) 90 

 (2) 18 

 (3) 168 

 (4) 72 

 (5) 42

(4) If radius and height of a cylinder increase by 20% and15% respectively. then what is the % change in curved surface area?

यदि एक बेलन की त्रिज्या और ऊंचाई क्रमशः 20% और15% बढ़ा दी जाती है तो बेलन का वक्रपृष्ठीय क्षेत्रफल क्या होगा ?

(1) 35% 

 (2) 32% 

 (3) 38% 

 (4) 42% 

 (5) Cannot be determined

(5) A and B can do a piece of work in 20 days and 30 days respectively. They started the work together but after 8 days they doing work in alternate days, started with B. how many days the work will be completed?

A और B किसी कार्य को क्रमशः 20 दिन और 30 दिन में कर सकते हैं। वे एक साथ काम शुरू करते है किया, किन्तु 8 दिन के पश्चात वे एकान्तर दिनों में कार्य करते है जिसमे B पहले शुरू करता है। कितने दिनों में कार्य पूरा हो जायेगा ?

(1) 12 

(2) 16 

(3) 14 

(4) 8 

 (5) 20

Q-(6-10) In the following questions find the value of the variables and state the correct relationship between them.

निम्नलिखित प्रश्न में चर का मान ज्ञात करें तथा उनके मध्य सही सम्बन्ध स्थापित कीजिए-

I. x²+12x + 36 = 0

II. y² + 16y + 64 = 0

(1) x > y

(2) x > y

(3) x < y

(4) x < y

(5) x = y or relationship cannot be established

(7) I. x² - 8x - 105 = 0

II. y² + 19y + 88 = 0

(1) x > y

(2) x > y

(3) x < y

(4) x < y

(5) x = y or relationship cannot be established

(8) I. x² = 20.25

II.

(1) x > y

(2) x > y

(3) x < y

(4) x <y

(5) x = y or relationship cannot be established

(9) I. 7x + 5y = 20

II. 14x - 15y = 2

(1) x > y

(2) x > y

(3) x < y

(4) x < y

(5) x = y or relationship cannot be established

(10) I. x² - 7x + 10 = 0

II. y² - 12y + 35 = 0

(1) x > y

(2) x > y

(3) x < y

(4) x < y

(5) x = y or relationship cannot be established

Answer Key-

Q-(1) Sol-(1)

Q-(2) Sol-(5)

1st day he read = 40%

2nd day he read =34 %

remaining = 100% - (40% +34%) = 26%

Last day he read =13%

13% = 52

1% = 4

100% = 400

Total page is 400.

Q-(3) Sol-(4)

Ratio of boys and girls = 100% : 75% = 4:3

Difference is 1 unit=30

So, 3 units = 90

If 20% absent, that’s mean 80% present.

So, present girls = 80% of 90 = 72

Q-(4) Sol-(3)

Q-(5) Sol-(2)

Together can do 5 units.

In 8 days they can do = 5 x 8 =40 unit

Remaining is = 60 – 40 = 20 unit

If they work alternately

1st day B will do 2 units.

2nd day A will do 3 units.

2 days they will do 5 units.

To complete 20 units, it will take = 8

Total days = 8 +8 =16 days

Q-(6) Sol-(1)

(x+6)² = 0 or x = -6,

(y+8)² = 0 or y = -8

Hence x > y

Q-(7) Sol-(1)

x = -7, 15 y = -8, -11

Hence x > y

Q-(8) Sol-(3)

x = 4.5, -4.5 y = 5.5

Hence x < y

Q-(9) Sol-(1)

Q-(10) Sol-(4)

x = 2, 5

y = 5, 7

Hence x <  y