SSC MTS | CHSL Quiz : Quantitative Aptitude | 21-07-2022

Dear Readers,

As SSC  MTS | CHSL  notification is out and candidates have started their preparation for this exam. Mahendras also has started special quizzes for this examination. This series of quizzes are based on the latest pattern of the   SSC  MTS | CHSL  examination. Regular practice of the questions included in the quizzes will boost up your preparations and it will be very helpful in scoring good marks in the examination.

Q- 1 Find the remainder when (6)¹²¹  is divided by 35.

A. 5

B. 7

C. 6

D. 18

(6)¹²¹  को 35 से भाग देने पर शेषफल ज्ञात कीजिए।

A. 5

B. 7

C. 6

D. 18

Q-2 Find the square root of

A.

B.

C.

D.

के वर्गमूल का मान ज्ञात कीजिये

A.

B.

C.

D.

Q-3 Find the sum of the

A. 15/16

B. 11/16

C. 11/12

D. 13/16

निम्न पदों का योग ज्ञात कीजिये-

A. 15/16

B. 11/16

C. 11/12

D. 13/16

Q-4 Find the lowest fraction –

6/7 , 7/9 , 4/5 , 5/7.

A. 5/7

B. 6/7

C. 7/9

D. 4/5

सबसे छोटी भिन्न ज्ञात कीजिये –

6/7 , 7/9 , 4/5 , 5/7.

A. 5/7

B. 6/7

C. 7/9

D. 4/5

Q-5 Find the number of zeros at the end of 1000 !.

A. 257

B. 249

C. 242

D. 245

1000! के अंत में शून्य की संख्या ज्ञात कीजिये।

A. 257

B. 249

C. 242

D. 245

Q-6‘A’ and ‘B’ can do a piece of work in 20 days and 12 days respectively. ‘A’ started the work alone and then after 4 days ‘B’ joined him till the completion of the work. How long did the work last ?

A. 6

B. 8

C. 10

D. 4

A’ और ’B’ क्रमशः 20 दिनों और 12 दिनों में एक काम कर सकते हैं। 'A' ने अकेले काम शुरू किया और फिर 4 दिनों के बाद 'B' ने काम पूरा होने तक उसे शामिल किया। काम कब तक चला?

A. 6

B. 8

C. 10

D. 4

Q-7 In triangle ABC, CD is angle bisector of ∠C, O is point in CD such that AO = AD and ∠ABC=63⁰, then find the ∠OAC

A. 830

B. 900

C. 630

D. 600

त्रिभुज ABC में, CD C का कोण द्विभाजक है, O, CD में बिंदु है जैसे AO = AD और ∠ABC=63⁰ , फिर ∠OAC का मान ज्ञात करिए.

A. 830

B. 900

C. 630

D. 600

Q-8 The length and breadth of rectangle is increased by 20% and 40% respectively, so find the net % change in its area?

A. 46%

B. -68%

C. 68%

D. 36%

आयत की लंबाई और चौड़ाई क्रमशः 20% और 40% बढ़ जाती है, इसलिए अपने क्षेत्रफल में शुद्ध% परिवर्तन ज्ञात करें?

A. 46%

B. -68%

C. 68%

D. 36%

Q-9 What is the Number of candidates who had applied if the ratio of selected to unselected was 14 : 25. If 35 less has applied and 10 less selected, the ratio of selected to unselected would have been 3 : 5?

A. 195

B. 205

C. 185

D. 175

उम्मीदवारों की संख्या क्या है जिन्होंने अपात्र के लिए चयनित औऱ अचय़नित का अनुपात 14: 25, अगर 35 कम आवेदन किया था और 10 कम चुने गए हैं, तो अचयनित के लिए चयनित का अनुपात 3: 5 होगा ?

A. 195

B. 205

C. 185

D. 175

Q-10 A man deposited same money in two banks separately, In these banks the rate of interest are 8% and 9.5% per annum and after 4 years he got the difference of S.I. from those banks Rs.54000. What was the money?

A. 5,00,000

B. 8,00,000

C. 9,00,000

D. 6,00,000

एक आदमी ने अलग-अलग दो बैंकों में एक ही पैसा जमा किया। इन बैंकों में ब्याज दर 8% और 9.5% प्रति वर्ष है और 4 साल बाद उन्हें उन बैंकों से 54000 रुपये में S.I का अंतर मिला। क्या पैसा था?

A. 5,00,000

B. 8,00,000

C. 9,00,000

D. 6,00,000

ANSWER:-

Q-1(3)

(6²)⁶⁰×6÷35 =1×6÷35

remainder = 6

(6²)⁶⁰×6÷35 =1×6÷35

शेष = 6

Q-2(1)

Q-3(3)

Q-4(1)

 6/7 = 0.85 , 7/9 = 0.77 , 4/5 = 0.8 , 5/7 = 0.71

Q-5(2)

Number of Zeroes = 240 + 40 + 8 + 1 = 249

Q-6(3)

LCM of 20 , 12 = 60unit(work)

A = 3w/d , B = 5w/d

4days work by A = 12W

Remaining work = 60 – 12= 48w

A+B = 8w/d

Time = 48/8

= 6days

Total time = 4 + 6

= 10days

LCM of 20 , 12 = 60 इकाई (कार्य)

A = 3w/d , B = 5w/d

A द्वारा 4 दिनों का कार्य = 12W

शेष कार्य = 60 – 12= 48w

A+B = 8w/d

समय = 48/8

= 6 दिन

कुल समय = 4 + 6

= 10 दिन

Q-7(3)

In triangle BDC ,

∠ADO = 63⁰  + x

∠AOD = x + y

AD = AO

∵ ∠ADO = ∠AOD

63⁰  + x = x + y

y = 630

त्रिभुज BDC ,

∠ADO = 63⁰  + x

∠AOD = x + y

AD = AO

∵ ∠ADO = ∠AOD

63⁰  + x = x + y

y = 630

Q-8(3)

(x + y + xy/100)%

X = 20% , y = 40%

Net % change = 68%

(x + y + xy/100)%

X = 20% , y = 40%

सकल % परिवर्तन = 68%

Q-9(1)

S : US = 14 : 25

S = 14x , US = 25x , total = 39x

(39x – 35)/(14x – 10) = 3/5

X = 5

39x = 39 x 5

= 195

Q-10(3)

1st bank SI = 8% x 4 = 32%

2nd bank SI = 9.5% x 4 = 38%

Diff = 6%

6% = 54,000

1% = 9,000

100% = 9,00, 000

पहले बैंक का SI = 8% x 4 = 32%

दूसरे बैंक का SI = 9.5% x 4 = 38%

अंतर= 6%

6% = 54,000

1% = 9,000

100% = 9,00, 000