Reasoning Ability Quiz For IBPS | RBI | SBI | NABARD | 25-08-2022

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Q.1-5. Study the following information carefully and answer the questions given below.

In a certain code language, “Great Near Frame” is written as “gt nr fe”, “Near Mortal Frame” is written as “nr ml fe” and “Flop Near Dream” is written as fp nr dm”.

प्र.1-5. निम्नलिखित जानकारी का ध्यानपूर्वक अध्ययन करें तथा नीचे दिए गए प्रश्नों के उत्तर दें।

एक निश्चित कोड भाषा में, “Great Near Frame” को “gt nr fe”, “Near Mortal Frame” को “nr ml fe” और “Flop Near Dream को “fp nr dm” लिखा जाता है।

Q.1. What is the code for “Eligible” in that code language?

प्र.1. उसी कोड भाषा में “Eligible” के लिए कोड क्या है?

(1) ee

(2) vs 

(3) sv 

(4) ve 

(5) ev

Q.2. How will ‘Physics’ be written in that code language?

प्र.2. उसी कोड भाषा में ‘Physics’ को कैसे लिखा जायेगा?

(1) hp 

 (2) lp 

 (3) ps 

 (4) so 

 (5) sp

Q.3. In the given code language, ‘my’ is the code of which of the following options?

प्र.3. दिए गए कोड भाषा में, ‘my’ निम्न विकल्पों में से किसका कोड है?

(1) Morn

 (2) Money 

 (3) Meet

(4) Moral 

 (5) Milk

Q.4. Which of the following is the code for “Fresh Water”?

प्र.4. निम्नलिखित में से कौन-सा “Fresh Water” के लिए कोड है?

(1) hm wt 

 (2) mt vo

(3) kt vo 

 (4) hf wo

(5) fh wr

Q.5. ‘Mind Blowing’ stands for –

प्र.5. Mind Blowing’ का अर्थ है-

(1) md bf 

 (2) md bl 

 (3) md bw

(4) md bg 

 (5) md gi

Q.6-10. In the following questions, the relationship between different elements is shown in the statement. These statements are followed by conclusions. Find which of the conclusions given below them is in doubtful condition.

निम्नलिखित प्रश्नों में, कथनों में विभिन्न तत्वों के बीच संबंध दर्शाये गये हैं। इन कथनों के बाद निष्कर्षों को दिया गया हैं। ज्ञात कीजिये कि दिये गये निष्कर्षों में से कौन-सा संदेहात्मक स्थिति में है।

Q.6. Statements: ZO ≤ EV≤ TW < FF ≤ SS= EE

Conclusions:

(1) EV< EE

(2) SS> EV

(3) ZO= EV

(4) TW > FF

(5) EE = SS

प्र.6. कथन: ZO≤ EV≤ TW< FF ≤ SS= EE

निष्कर्ष:

(1) EV< EE

(2) SS> EV

(3) ZO= EV

(4) TW> FF

(5) EE = SS

Q.7. Statements:

EE = FF ≤ SS ≤ TH > EV > ZO

Conclusions:

(1) FF ≤ EV

(2) EE ≤ SS

(3) FF = EE

(4) TH > ZO

(5) TH ≥ EE

प्र.7. कथन: EE = FF ≤ SS ≤ TH > EV >ZO

निष्कर्ष:

(1) FF ≤ EV

(2) EE ≤ SS

(3) FF = EE

(4) TH > ZO

(5) TH ≥ EE

Q.8. Statements:

FU ≤ TW > EV ≤ TL ≤ ST ≤ EE

Conclusions:

(1) TL ≤ EE

(2) EE = TW

(3) FU > EV

(4) FU = EV

(5) 2, 3 and 4

प्र.8. कथन: FU ≤ TW > EV ≤ TL ≤ ST ≤ EE

निष्कर्ष:

(1) TL ≤ EE

(2) EE = TW

(3) FU > EV

(4) FU = EV

(5) 2, 3 और 4

Q.9. Statements: FU ≤ TW < EV ≤ TL ≤ ST ≤ EE

Conclusions:

(1) EV ≤ EE

(2) EE > FU

(3) EE = EV

(4) FU > TW

(5) ST < TW

प्र.9. कथन: FU ≤TW< EV ≤ TL ≤ ST≤ EE

निष्कर्ष:

(1) EV ≤ EE

(2) EE > FU

(3) EE = EV

(4) FU > TW

(5) ST < TW

Q.10. Statements: TH ≤ FF ≤ NT ≥ FU = EV > TW

Conclusions:

(1) TH > FF

(2) FU > TW

(3) NT > TW

(4) NT > EV

(5) FF > FU

प्र.10. कथन: TH≤ FF≤ NT ≥ FU = EV > TW

निष्कर्ष:

(1) TH> FF

(2) FU > TW

(3) NT > TW

(4) NT > EV

(5) FF > FU

Answer/ उत्तर:-

In word = the first and the last letter of each word.

शब्द में = प्रत्येक शब्द के पहले और अंतिम अक्षर।

Q 1. (1)

 

Q. 2. (3) 

Q. 3. (2)

Q 4. (5) 

 Q. 5. (4)

Q.6. (3) 

 Q.7. (1) 

 Q.8. (5) 

 Q.9. (3) 

 Q.10. (5)